{"id":125542,"date":"2023-09-04T01:38:00","date_gmt":"2023-09-03T20:08:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125542"},"modified":"2023-11-01T11:14:08","modified_gmt":"2023-11-01T05:44:08","slug":"rd-sharma-class-9-solutions-chapter-6-exercise-6-3","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-exercise-6-3\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125544\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-Exercise-6.3.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-Exercise-6.3.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-6-Exercise-6.3-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3: <\/strong>Unable to score good despite reading too many books for your Class 9 Maths exam? Maybe you just need one good for that and i.e., <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths<\/a>. There are many benefits of studying the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-6-factorization-of-polynomials\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 6<\/a> Exercise 6.3 which includes to the point solutions, credible and as per the curren CBSE Syllabus and more. To know more, read the whole blog.\u00a0<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e191cbac1fc\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" 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href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-exercise-6-3\/#from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-6-exercise-63\" title=\"From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?\">From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-exercise-6-3\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-6-exercise-63\" title=\"How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?\">How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-9-solutions-chapter-6-exercise-63-pdf\"><\/span><strong>Download RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-6-Ex-6.3.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-6-Ex-6.3.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-6-exercise-63\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Question 1.<br \/>f(x) = x<sup>3<\/sup>\u00a0+ 4x<sup>2<\/sup>\u00a0\u2013 3x + 10, g(x) = x + 4<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1953\/45580230032_9fb3061dbc_o.png\" alt=\"RD Sharma Solutions Class 9 Chapter 6 Factorisation of Polynomials\" width=\"333\" height=\"296\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1920\/43813181210_40b7e2a9c2_o.png\" alt=\"RD Sharma Class 9 PDF Chapter 6 Factorisation of Polynomials\" width=\"172\" height=\"25\" \/><\/p>\n<p>Question 2.<br \/>f(x) \u2013 4x<sup>4<\/sup>\u00a0\u2013 3x<sup>3<\/sup>\u00a0\u2013 2x<sup>2<\/sup><em>\u00a0+\u00a0<\/em>x \u2013 7, g(x)<em>\u00a0=\u00a0<\/em>x<em>\u00a0\u2013\u00a0<\/em><em>1<br \/><\/em>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1950\/45580229632_478df790bc_o.png\" alt=\"Factorisation of Algebraic Expressions Class 9 RD Sharma Solutions\" width=\"341\" height=\"425\" \/><\/p>\n<p>Question 3.<br \/>f(x) = 2x<sup>4<\/sup>\u00a0\u2013 6X<sup>3<\/sup>\u00a0+ 2x<sup>2<\/sup>\u00a0\u2013 x + 2, ,g(x) = x + 2<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1957\/43813181100_cb57f82c62_o.png\" alt=\"RD Sharma Class 9 Solution Chapter 6 Factorisation of Polynomials\" width=\"368\" height=\"478\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1972\/45580228772_e652ee96b6_o.png\" alt=\"Class 9 RD Sharma Solutions Chapter 6 Factorisation of Polynomials\" width=\"194\" height=\"28\" \/><\/p>\n<p>Question 4.<br \/>f(x) = 4x<sup>3<\/sup>\u00a0\u2013 12x<sup>2<\/sup>\u00a0+ 14x \u2013 3, g(x) = 2x \u2013 1<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1952\/43813180990_a062119b53_o.png\" alt=\"Class 9 Maths Chapter 6 Factorisation of Polynomials RD Sharma Solutions\" width=\"342\" height=\"667\" \/><\/p>\n<p>Question 5.<br \/>f(x) = x<sup>3<\/sup>\u00a0\u2013 6x<sup>2<\/sup>\u00a0+ 2x \u2013 4, g(x) = 1 \u2013 2x<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1980\/45580228162_f1efbac499_o.png\" alt=\"RD Sharma Book Class 9 PDF Free Download Chapter 6 Factorisation of Polynomials\" width=\"338\" height=\"230\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1919\/43813180800_7c46abec2f_o.png\" alt=\"RD Sharma Class 9 Book Chapter 6 Factorisation of Polynomials\" width=\"300\" height=\"534\" \/><\/p>\n<p>Question 6.<br \/>f(x) = x<sup>4<\/sup>\u00a0\u2013 3x<sup>2<\/sup>\u00a0+ 4, g(x) = x \u2013 2<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1964\/45580227592_e83474840e_o.png\" alt=\"Factorisation of Polynomials With Solutions PDF RD Sharma Class 9 Solutions\" width=\"289\" height=\"402\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1962\/43813180590_f92cc211cd_o.png\" alt=\"RD Sharma Class 9 Maths Book Questions Chapter 6 Factorisation of Polynomials\" width=\"157\" height=\"30\" \/><\/p>\n<p>Question 7.<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1939\/45580227202_62e9ae600e_o.png\" alt=\"RD Sharma Mathematics Class 9 Solutions Chapter 6 Factorisation of Polynomials\" width=\"297\" height=\"51\" \/><br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1973\/43813180560_a7827f28cf_o.png\" alt=\"Solution Of Rd Sharma Class 9 Chapter 6 Factorisation of Polynomials\" width=\"349\" height=\"695\" \/><\/p>\n<p>Question 8.<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1968\/45580226872_341acbb2f5_o.png\" alt=\"RD Sharma Math Solution Class 9 Chapter 6 Factorisation of Polynomials\" width=\"323\" height=\"106\" \/><br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1933\/43813180460_08534c2dbf_o.png\" alt=\"RD Sharma Class 9 Questions Chapter 6 Factorisation of Polynomials\" width=\"295\" height=\"52\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1975\/45580226742_a466d407cf_o.png\" alt=\"Maths RD Sharma Class 9 Chapter 6 Factorisation of Polynomials\" width=\"353\" height=\"552\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1913\/43813180290_1ce069a948_o.png\" alt=\"RD Sharma Class 9 Chapter 6 Factorisation of Polynomials\" width=\"331\" height=\"283\" \/><\/p>\n<p>Question 9.<br \/>If the polynomials 2x<sup>3<\/sup>\u00a0+ ax<sup>2<\/sup>\u00a0+ 3x \u2013 5 and x<sup>3\u00a0<\/sup>+ x<sup>2<\/sup>\u00a0\u2013 4x + a leave the same remainder when divided by x \u2013 2, find the value of a.<br \/>Solution:<br \/>Let f(x) = 2x<sup>3<\/sup>\u00a0+ ax<sup>2<\/sup>\u00a0+ 3x \u2013 5<br \/>g(x) = x<sup>3<\/sup>+x<sup>2<\/sup>-4x + a<br \/>q(x) = x \u2013\u00a0 2 \u21d2 x-2 = 0\u00a0 \u21d2x = 2<br \/>\u2234 Remainder =f(2) = 2(2)<sup>3<\/sup>\u00a0+ a(2)<sup>2<\/sup>\u00a0+ 3 x 2-5<br \/>= 2 x 8 4-a x 4 + 3 x 2-5<br \/>= 16 + 4a + 6 \u2013 5<br \/>= 4a +17<br \/>and g(2) = (2)<sup>3<\/sup>\u00a0+ (2)<sup>2<\/sup>\u00a0-4\u00d72 + a<br \/>= 8 + 4 \u2013 8 + a = a + 4<br \/>\u2235\u00a0 In both cases, remainder are same<br \/>\u2234\u00a0 4a + 17 = a + 4<br \/>\u21d2\u00a0 4a \u2013 a = 4 \u2013 17 \u21d2\u00a0 3a = -13<br \/>\u21d2 a =\u00a0<span id=\"MathJax-Element-1-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-1\" class=\"math\"><span id=\"MathJax-Span-2\" class=\"mrow\"><span id=\"MathJax-Span-3\" class=\"mfrac\"><span id=\"MathJax-Span-4\" class=\"mrow\"><span id=\"MathJax-Span-5\" class=\"mo\">\u2212<\/span><span id=\"MathJax-Span-6\" class=\"mn\">13<\/span><\/span><span id=\"MathJax-Span-7\" class=\"mn\">3<\/span><\/span><\/span><\/span><\/span><br \/>Hence a =\u00a0<span id=\"MathJax-Element-2-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-8\" class=\"math\"><span id=\"MathJax-Span-9\" class=\"mrow\"><span id=\"MathJax-Span-10\" class=\"mfrac\"><span id=\"MathJax-Span-11\" class=\"mrow\"><span id=\"MathJax-Span-12\" class=\"mo\">\u2212<\/span><span id=\"MathJax-Span-13\" class=\"mn\">13<\/span><\/span><span id=\"MathJax-Span-14\" class=\"mn\">3<\/span><\/span><\/span><\/span><\/span><\/p>\n<p>Question 10.<br \/>If the polynomials ax<sup>3<\/sup>\u00a0+ 3x<sup>2<\/sup>\u00a0\u2013 13 and 2x<sup>3<\/sup>\u00a0\u2013 5x + a, when divided by (x \u2013 2), leave the same remainders, find the value of a.<br \/>Solution:<br \/>Let p(x) = ax<sup>3<\/sup>\u00a0+ 3x<sup>2<\/sup>\u00a0\u2013 13<br \/>q(x) = 2x<sup>3\u00a0<\/sup>\u20135x + a<br \/>and divisor g(x) = x \u2013 2<br \/>x-2 = 0<br \/>\u21d2 x = 2<br \/>\u2234 Remainder = p(2) = a(2)<sup>3<\/sup>\u00a0+ 3(2)<sup>2<\/sup>\u00a0\u2013 13<br \/>= 8a + 12 \u2013 13 = 8a \u2013 1<br \/>and q( 2) = 2(2)<sup>3<\/sup>\u00a0\u2013 5\u00d72 + a=16-10 + a<br \/>= 6 + a<br \/>\u2235\u00a0 In each case remainder is same<br \/>\u2234 8a \u2013 1 = 6 + a<br \/>8a \u2013 a = 6 + 1<br \/>\u21d2\u00a0 7a = 7<br \/>\u21d2 a =\u00a0<span id=\"MathJax-Element-3-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-15\" class=\"math\"><span id=\"MathJax-Span-16\" class=\"mrow\"><span id=\"MathJax-Span-17\" class=\"mfrac\"><span id=\"MathJax-Span-18\" class=\"mn\">7<\/span><span id=\"MathJax-Span-19\" class=\"mn\">7<\/span><\/span><\/span><\/span><\/span>= 1<br \/>\u2234 a = 1<\/p>\n<p>Question 11.<br \/>Find the remainder when x<sup>3<\/sup>\u00a0+ 3x<sup>2<\/sup>\u00a0+ 3x + 1 is divided by<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1948\/45580226082_b93697d48d_o.png\" alt=\"RD Sharma Class 9 Solutions Chapter 6 Factorisation of Polynomials\" width=\"386\" height=\"104\" \/><br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1947\/43813180140_dea6c03145_o.png\" alt=\"RD Sharma Solutions Class 9 Chapter 6 Factorisation of Polynomials\" width=\"342\" height=\"98\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1922\/45580225942_d8f8dbd64c_o.png\" alt=\"RD Sharma Class 9 PDF Chapter 6 Factorisation of Polynomials\" height=\"598\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1904\/43813180010_d3dc5d3728_o.png\" alt=\"Factorisation of Algebraic Expressions Class 9 RD Sharma Solutions\" width=\"370\" height=\"375\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1954\/45580225442_a73df1aa16_o.png\" alt=\"RD Sharma Class 9 Solution Chapter 6 Factorisation of Polynomials\" width=\"241\" height=\"224\" \/><\/p>\n<p>Question 12.<br \/>The polynomials ax<sup>3<\/sup>\u00a0+ 3a-<sup>2<\/sup>\u00a0\u2013 3 and 2x<sup>3<\/sup>\u00a0\u2013 5x + a when divided by (x \u2013 4) leave the remainders R<sub>1<\/sub>\u00a0and R<sub>2<\/sub>, respectively. Find the values of a in each case of the following cases, if<br \/>(i) R<sub>1<\/sub>\u00a0= R<sub>2<\/sub><br \/>(ii) R<sub>1<\/sub>\u00a0+ R<sub>2<\/sub>\u00a0= 0<br \/>(iii) 2R<sub>1<\/sub>\u00a0\u2013 R<sub>2<\/sub>\u00a0= 0.<br \/>Solution:<br \/><img src=\"https:\/\/farm2.staticflickr.com\/1916\/45580225402_336244c8e5_o.png\" alt=\"Class 9 RD Sharma Solutions Chapter 6 Factorisation of Polynomials\" width=\"366\" height=\"580\" \/><br \/><img src=\"https:\/\/farm2.staticflickr.com\/1933\/45580224762_2dbedb4bb1_o.png\" alt=\"Class 9 Maths Chapter 6 Factorisation of Polynomials RD Sharma Solutions\" width=\"282\" height=\"169\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"rd-sharma-class-9-maths-solutions-factorization-of-polynomials-exercise-63\"><\/span>RD Sharma class 9 maths Solutions Factorization of Polynomials Exercise-6.3<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><img src=\"https:\/\/farm8.staticflickr.com\/7623\/16840938789_9e19ec6ac4_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-1\" width=\"475\" height=\"357\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8746\/16839379708_4de45b5d06_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-2\" width=\"476\" height=\"346\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7645\/16407012773_d606f7d403_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-3\" width=\"473\" height=\"336\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7620\/17001168056_02bb336969_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-4\" width=\"468\" height=\"352\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7607\/16404736164_17abcc2e92_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-5\" width=\"467\" height=\"339\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8703\/16819743357_f22669bccb_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-6\" width=\"464\" height=\"346\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8697\/16839621430_529030f7cd_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-7\" width=\"473\" height=\"300\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7603\/17026295081_c4b5843ba5_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-8\" width=\"474\" height=\"391\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8729\/17025710722_c6b8aff109_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-9\" width=\"479\" height=\"344\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8750\/16839621320_8813b1f876_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-10\" width=\"468\" height=\"315\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7584\/16819743117_e063231cb7_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-10_1\" width=\"415\" height=\"491\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8748\/17025710542_290bfec45b_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-11\" width=\"408\" height=\"155\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8719\/16819743067_e1d371e087_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-11_1\" width=\"411\" height=\"175\" \/><br \/><img src=\"https:\/\/farm9.staticflickr.com\/8704\/16407012303_142a0b9289_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-12_1\" width=\"416\" height=\"385\" \/><br \/><img src=\"https:\/\/farm8.staticflickr.com\/7640\/17001167636_f6b7ae1acb_o.png\" alt=\"RD-Sharma-class 9-maths-Solutions-chapter 6-Factorization of Polynomials -Exercise 6.3-Question-12_2\" width=\"412\" height=\"258\" \/><\/p>\n<p>This is the complete blog on RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exam, ask in the comments.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-6-exercise-63\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>\u00a0<\/p>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631102288003\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-access-the-rd-sharma-class-9-solutions-chapter-6-exercise-63-pdf-offline\"><\/span>Can I access the RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3\u00a0PDF offline?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Once you have downloaded the PDF online, you can access it offline as well.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631102319675\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-6-exercise-63\"><\/span>From where can I download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631102352489\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-class-9-solutions-chapter-6-exercise-63\"><\/span>How much does it cost to download the PDF of RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3: Unable to score good despite reading too many books for your Class 9 Maths exam? Maybe you just need one good for that and i.e., RD Sharma Solutions Class 9 Maths. There are many benefits of studying the RD Sharma Class 9 Solutions Chapter 6 Exercise &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-6-exercise-6-3\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 6 Exercise 6.3 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":125544,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125542"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125542"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125542\/revisions"}],"predecessor-version":[{"id":500433,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125542\/revisions\/500433"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125544"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125542"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125542"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125542"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}