{"id":125485,"date":"2023-04-06T03:45:00","date_gmt":"2023-04-05T22:15:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125485"},"modified":"2026-05-02T06:25:51","modified_gmt":"2026-05-02T00:55:51","slug":"rd-sharma-class-9-solutions-chapter-5-mcqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-5-mcqs\/","title":{"rendered":"RD Sharma Class 9 Solutions: Complete Guide [2026]"},"content":{"rendered":"<p><script type=\"application\/ld+json\">\n{\n  \"@context\": \"https:\/\/schema.org\",\n  \"@type\": \"Article\",\n  \"headline\": \"RD Sharma Class 9 Solutions: Complete Guide [2026]\",\n  \"description\": \"Comprehensive RD Sharma Class 9 Solutions for Maths, designed by experts according to the latest CBSE syllabus 2026. Master algebraic factorization and score high in your exams.\",\n  \"author\": {\n    \"@type\": \"Organization\",\n    \"name\": \"KopyKitab\"\n  },\n  \"publisher\": {\n    \"@type\": \"Organization\",\n    \"name\": \"KopyKitab\",\n    \"url\": \"https:\/\/www.kopykitab.com\"\n  },\n  \"datePublished\": \"2026-05-02\",\n  \"dateModified\": \"2026-05-02\"\n}\n<\/script><\/p>\n<div class=\"freshness-block\" style=\"background:#e8f5e9;padding:15px;border-left:4px solid #4caf50;margin:20px 0;border-radius:4px;\">\n<strong>Last Updated:<\/strong> May 02, 2026 | This article has been updated with the latest information for 2026.\n<\/div>\n<p><img alt=\"RD Sharma Class 9 Solutions Chapter 5 MCQS\" class=\"alignnone size-full wp-image-125629\" height=\"675\" loading=\"eager\" sizes=\"(max-width: 1200px) 100vw, 1200px\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-5-MCQS.jpg\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-5-MCQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-5-MCQS-768x432.jpg 768w\" width=\"1200\"\/><\/p>\n<div class=\"key-takeaways\" style=\"background:#e3f2fd;padding:20px;border-left:4px solid #1976d2;margin:20px 0;border-radius:4px;\">\n<h3 style=\"margin:0 0 12px;color:#1565c0;\"><span class=\"ez-toc-section\" id=\"key-takeaways\"><\/span>Key Takeaways<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul style=\"margin:0;padding-left:20px;\">\n<li>Access answers of RD Sharma Class 9 Solutions Chapter 5 MCQS<\/li>\n<li>Chapter 5 Factorization Techniques Overview<\/li>\n<li>Board Exam Importance and Weightage<\/li>\n<li>Difficulty Level Progression<\/li>\n<\/ul>\n<\/div>\n<p><strong>Read more:<\/strong> <a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\">RD Sharma \u2014 Complete Guide<\/a><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 5 MCQS<\/strong>: Subject matter experts have designed these easy-to-understand solutions for you in the <a href=\"\/blog\/rd-sharma-class-9-solutions-for-maths\/\" rel=\"noopener\" target=\"_blank\">RD Sharma Solutions Class 9 Maths<\/a>. All the solutions are as per the current CBSE Syllabus 2026. You can clear your concepts and score good marks in your Maths exam with <a href=\"\/blog\/rd-sharma-solutions-class-9-maths-chapter-5-factorization-of-algebraic-expressions\/\" rel=\"noopener\" target=\"_blank\">RD Sharma Class 9 Solutions Chapter 5<\/a> MCQS.<\/p>\n<p>Algebra ke factorization topic mein mastery pane ke liye, ye MCQs bilkul perfect hain. Chapter 5 mein algebraic expressions ko factorize karna sikhaya gaya hai jo Class 9 students ke liye bohot important hai. These questions help you understand different factorization techniques jaise common factors, grouping method, aur special identities ka use.<\/p>\n<div class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\" id=\"ez-toc-container\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<p><span class=\"ez-toc-title-toggle\"><a aria-label=\"ez-toc-toggle-icon-1\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" href=\"#\"><label aria-label=\"Table of Content\" for=\"item-69f54acd8b270\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg class=\"list-377408\" fill=\"none\" height=\"20px\" style=\"fill: #000000;color:#000000\" viewbox=\"0 0 24 24\" width=\"20px\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg baseprofile=\"tiny\" class=\"arrow-unsorted-368013\" height=\"10px\" style=\"fill: #000000;color:#000000\" version=\"1.2\" viewbox=\"0 0 24 24\" width=\"10px\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"><\/path><\/svg><\/span><\/label><input id=\"item-69f54acd8b270\" type=\"checkbox\"\/><\/a><\/span><\/div>\n<nav>\n<ul class=\"ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default\">\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-1\" href=\"#access-answers-of-rd-sharma-class-9-solutions-chapter-5-mcqs\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 5 MCQS\">Access answers of RD Sharma Class 9 Solutions Chapter 5 MCQS<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-2\" href=\"#chapter-5-factorization-techniques-overview\" title=\"Chapter 5 Factorization Techniques Overview\">Chapter 5 Factorization Techniques Overview<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-3\" href=\"#board-exam-importance-and-weightage\" title=\"Board Exam Importance and Weightage\">Board Exam Importance and Weightage<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-4\" href=\"#difficulty-level-progression\" title=\"Difficulty Level Progression\">Difficulty Level Progression<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-2\"><a class=\"ez-toc-link ez-toc-heading-5\" href=\"#faqs-on-rd-sharma-class-9-solutions-chapter-5-mcqs\" title=\"FAQs on RD Sharma Class 9 Solutions Chapter 5 MCQS\">FAQs on RD Sharma Class 9 Solutions Chapter 5 MCQS<\/a>\n<ul class=\"ez-toc-list-level-3\">\n<li class=\"ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-6\" href=\"#how-many-questions-exist-in-rd-sharma-class-9-solutions-chapter-5-mcqs\" title=\"How many questions exist in RD Sharma Class 9 Solutions Chapter 5 MCQs?\">How many questions exist in RD Sharma Class 9 Solutions Chapter 5 MCQs?<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-7\" href=\"#is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-5-mcqs\" title=\"Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 5 MCQs?\">Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 5 MCQs?<\/a><\/li>\n<li class=\"ez-toc-page-1 ez-toc-heading-level-3\"><a class=\"ez-toc-link ez-toc-heading-8\" href=\"#are-the-solutions-rd-sharma-class-9-solutions-chapter-5-mcqs-relevant\" title=\"Are the solutions RD Sharma Class 9 Solutions Chapter 5 MCQs relevant?\">Are the solutions RD Sharma Class 9 Solutions Chapter 5 MCQs relevant?<\/a><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/nav>\n<\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"access-answers-of-RD-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 5 MCQS<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Yahan par aapko complete <a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\">solutions<\/a> milenge jo step-by-step explain kiye gaye hain. Har question ka detailed solution diya gaya hai taki aap concept clear kar sako. Ye MCQs specially designed hain CBSE board exam pattern ke according.<\/p>\n<p><strong>Mark the correct alternative in each of the following:<br \/><\/strong><strong>Question 1.<br \/><\/strong><strong>The factors of x<sup>3<\/sup> \u2013 x<sup>2<\/sup>y -xy<sup>2<\/sup> + y<sup>3<\/sup> are<\/strong><br \/><strong>(a) (x + y) (x<sup>2<\/sup> -xy + y<sup>2<\/sup>)<\/strong><br \/><strong>(b) (x+y)(x<sup>2<\/sup> + xy + y<sup>2<\/sup>)<\/strong><br \/><strong>(c) (x + y)<sup>2<\/sup> (x \u2013 y)<\/strong><br \/><strong>(d) (x \u2013 y)<sup>2<\/sup> (x + y)<br \/><\/strong><strong>Solution:<br \/><\/strong>x<sup>3<\/sup> \u2013 x<sup>2<\/sup>y \u2013 xy<sup>2<\/sup> + y<sup>3<br \/><\/sup><em>= x<sup>3<\/sup> + <\/em>y<sup>3<\/sup> \u2013 x<sup>2<\/sup>y \u2013 xy<sup>2<br \/><\/sup>= (x + y) (x<sup>2<\/sup> -xy + y<sup>2<\/sup>)- xy(x + y)<br \/>= (x + y) (x<sup>2<\/sup> \u2013 xy + y<sup>2<\/sup> \u2013 xy)<br \/>= (x + y) (x<sup>2<\/sup> \u2013 2xy + y<sup>2<\/sup>)<br \/>= (x + y) (x \u2013 y)<sup>2      <strong> <\/strong><\/sup><strong>(d)<\/strong><\/p>\n<p>Is question mein hum grouping method use kar rahe hain. Pehle terms ko rearrange kiya, phir common factors nikale. Ye technique bohot useful hai complex expressions ko factorize karne ke liye.<\/p>\n<p><strong>Question 2.<br \/><\/strong><strong>The factors of x<sup>3<\/sup> \u2013 1 +y<sup>3<\/sup> + 3xy are<\/strong><br \/><strong>(a) (x \u2013 1 + y)  (x<sup>2<\/sup> + 1 + y<sup>2<\/sup> + x + y \u2013 xy)<\/strong><br \/><strong>(b) (x + y + 1)  (x<sup>2<\/sup> + y<sup>2<\/sup> + 1- xy \u2013 x \u2013 y)<\/strong><br \/><strong>(c) (x \u2013 1 + y)   (x<sup>2<\/sup> \u2013 1 \u2013 y<sup>2 <\/sup>+ x + y + xy)<\/strong><br \/><strong>(d) 3(x + y \u2013 1) (x<sup>2<\/sup> + y<sup>2<\/sup> \u2013 1)<br \/><\/strong><strong>Solution:<br \/><\/strong>x<sup>3<\/sup> \u2013 1 + y<sup>3<\/sup> + 3xy<br \/>= (x)<sup>3<\/sup> + (-1)<sup>3<\/sup> + (y)<sup>3<\/sup> \u2013 3 x  x  x (-1) x y<br \/>= (x \u2013 1 + y) (x<sup>2<\/sup> + 1 + y<sup>2<\/sup> + x + y \u2013 xy)<br \/>= (x- 1 + y) (x<sup>2<\/sup>+ 1 + y<sup>2<\/sup> + x + y \u2013 xy)     <strong> (a)<\/strong><\/p>\n<p>Yahan sum of cubes identity ka use kiya gaya hai: a\u00b3 + b\u00b3 + c\u00b3 &#8211; 3abc = (a + b + c)(a\u00b2 + b\u00b2 + c\u00b2 &#8211; ab &#8211; bc &#8211; ca). Ye formula yaad rakhna zaroori hai.<\/p>\n<div class=\"code-block code-block-2\"> <\/div>\n<p><strong>Question 3.<br \/><\/strong><strong>The factors of 8a<sup>3<\/sup> + b<sup>3<\/sup> \u2013 6ab + 1 are<\/strong><br \/><strong>(a) (2a + b \u2013 1) (4a<sup>2<\/sup> + b<sup>2<\/sup> + 1 \u2013 3ab \u2013 2a)<\/strong><br \/><strong>(b) (2a \u2013 b + 1) (4a<sup>2<\/sup> + b<sup>2<\/sup> \u2013 4ab + 1 \u2013 2a + b)<\/strong><br \/><strong>(c) (2a + b+1) (4a<sup>2<\/sup> + b<sup>2<\/sup> + 1 \u2013 2ab \u2013 b \u2013 2a)<\/strong><br \/><strong>(d) (2a \u2013 1 + b)(4a<sup>2<\/sup> + 1 \u2013 4a \u2013 b \u2013 2ab)<br \/><\/strong><strong>Solution:<br \/><\/strong>8a<sup>3<\/sup> + b<sup>3<\/sup> \u2013 6ab + 1<br \/>= (2a)<sup>3<\/sup> + (b)<sup>3<\/sup> + (1)<sup>3<\/sup> \u2013 3 x 2a x b x 1<br \/>= (2a + b + 1) [(2a)<sup>2<\/sup> + b<sup>2<\/sup>+1-2a x b- b x 1 \u2013 1 x 2a]<br \/>= (2a + b + 1) (4a<sup>2<\/sup> + b<sup>2<\/sup>+1-2ab-b- 2a)           <strong> (c)<\/strong><\/p>\n<p>Is type ke questions mein pehle check karna chahiye ki kya expression sum of cubes ke form mein convert ho sakti hai. Agar coefficient different hain to unhe perfect cubes banane ki koshish karni chahiye.<\/p>\n<p><strong>Question 4.<br \/><\/strong><strong>(x + y)<sup>3<\/sup> \u2013 (x \u2013 v)<sup>3<\/sup> can be factorized as<\/strong><br \/><strong>(a) 2y (3x<sup>2<\/sup> + y<sup>2<\/sup>)                <\/strong><br \/><strong>(b) 2x (3x<sup>2<\/sup> + y<sup>2<\/sup>)<\/strong><br \/><strong>(c) 2y (3y<sup>2<\/sup> + x<sup>2<\/sup>)                <\/strong><br \/><strong>(d) 2x (x<sup>2<\/sup> + 3y<sup>2<\/sup>)<\/strong><br \/><strong>Solution:<br \/><\/strong>(x + y)<sup>3<\/sup> \u2013 (x \u2013 y)<sup>3<br \/><\/sup>= (x + y -x + y) [(x + y)<sup>2<\/sup> + (x +y) (x -y) + (x \u2013 y)<sup>2<\/sup>]<br \/>= 2y(x<sup>2<\/sup> + y<sup>2<\/sup> + 2xy + x<sup>2<\/sup>-y<sup>2<\/sup> + x<sup>2<\/sup>+y<sup>2<\/sup> \u2013 2xy)<br \/>= 2y(3x<sup>2<\/sup> + y<sup>2<\/sup>)        <strong>  (a)<\/strong><\/p>\n<p>Difference of cubes formula: a\u00b3 &#8211; b\u00b3 = (a &#8211; b)(a\u00b2 + ab + b\u00b2). Is question mein a = (x + y) aur b = (x &#8211; y) hai.<\/p>\n<p><strong>Question 5.<br \/><\/strong><strong>The expression (a \u2013 b)<sup>3<\/sup> + (b \u2013 c)<sup>3<\/sup> + (c \u2013 a)<sup>3<\/sup> can be factorized as<\/strong><br \/><strong>(a) (a -b) (b- c) (c \u2013 a) <\/strong><br \/><strong>(b) 3(a \u2013 b) (b \u2013 c) (c \u2013 a)<\/strong><br \/><strong>(c) -3(a \u2013 b) (b \u2013 c) (a \u2013 a)<\/strong><br \/><strong>(d) (a + b + c) (a<sup>2<\/sup> + b<sup>2<\/sup> + c<sup>2<\/sup> \u2013 ab \u2013 bc \u2013 ca)<\/strong><br \/><strong>Solution:<br \/><\/strong>(a \u2013 b)<sup>3<\/sup> + (b \u2013 c)<sup>3<\/sup> + (c \u2013 a)<sup>3<br \/><\/sup>Let a \u2013 b = x, b \u2013 c = y, c \u2013 a = z<br \/>\u2234 x<sup>3<\/sup> + y<sup>3<\/sup> + z<sup>3<br \/><\/sup>x+y + z = a- b + b- c + c \u2013 a = 0<br \/>\u2234 x<sup>3<\/sup> +y<sup>3<\/sup> + z<sup>3<\/sup> = 3xyz<br \/>(a \u2013 b)<sup>3<\/sup> + (b \u2013 c)<sup>3<\/sup> + (c \u2013 a)<sup>3<br \/><\/sup>= 3 (a \u2013 b) (b \u2013 c) (c \u2013 a)      <strong>  (b)<\/strong><\/p>\n<p>Ye special case hai jahan x + y + z = 0 hota hai to x\u00b3 + y\u00b3 + z\u00b3 = 3xyz. Ye identity bohot important hai aur exam mein frequently aati hai.<\/p>\n<p><strong>Question 6.<\/strong><br \/><img &quot;=\"\" blog=\"\" category=\"\" class=\"alignnone size-full wp-image-65872\" height=\"450\" https:=\"\" loading=\"lazy\" rd-sharma-solutions=\"\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/&lt;a href=\" width=\"800\" www.kopykitab.com=\"\" alt=\"\">RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.1.png&#8221; sizes=&#8221;(max-width: 554px) 100vw, 554px&#8221; srcset=&#8221;https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.1.png 554w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.1-300&#215;51.png 300w&#8221; alt=&#8221;RD Sharma Class 9 Solutions Chapter 5 Factorisation of Algebraic Expressions MCQS Q6.1&#8243; width=&#8221;554&#8243; height=&#8221;94&#8243; \/&gt;<br \/><strong>Solution:<\/strong><br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 5 Factorisation of Algebraic Expressions MCQS Q6.2\" class=\"alignnone size-full wp-image-65873\" height=\"239\" loading=\"lazy\" sizes=\"(max-width: 710px) 100vw, 710px\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.2.png\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.2.png 710w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q6.2-300x101.png 300w\" width=\"710\"\/><\/p>\n<p><strong>Question 7.<\/strong><br \/><img &quot;=\"\" blog=\"\" category=\"\" class=\"alignnone size-full wp-image-65874\" height=\"450\" https:=\"\" loading=\"lazy\" rd-sharma-solutions=\"\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/&lt;a href=\" width=\"800\" www.kopykitab.com=\"\" alt=\"\">RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.1.png&#8221; sizes=&#8221;(max-width: 576px) 100vw, 576px&#8221; srcset=&#8221;https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.1.png 576w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.1-300&#215;54.png 300w&#8221; alt=&#8221;RD Sharma Class 9 Solutions Chapter 5 Factorisation of Algebraic Expressions MCQS Q7.1&#8243; width=&#8221;576&#8243; height=&#8221;103&#8243; \/&gt;<br \/><strong>Solution:<\/strong><br \/><img alt=\"RD Sharma Class 9 Solutions Chapter 5 Factorisation of Algebraic Expressions MCQS Q7.2\" class=\"alignnone size-full wp-image-65875\" height=\"170\" loading=\"lazy\" sizes=\"(max-width: 714px) 100vw, 714px\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.2.png\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.2.png 714w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2018\/06\/RD-Sharma-Class-9-Solutions-Chapter-5-Factorisation-of-Algebraic-Expressions-MCQS-Q7.2-300x71.png 300w\" width=\"714\"\/><\/p>\n<p><strong>Question 8.<br \/><\/strong><strong>The factors of a<sup>2<\/sup> \u2013 1 \u2013 2x \u2013 x<sup>2<\/sup> are<\/strong><br \/><strong>(a) (a \u2013 x + 1) (a \u2013 x \u2013 1)                                <\/strong><br \/><strong>(b) (a + x \u2013 1) (a \u2013 x + 1)<\/strong><br \/><strong>(c) (a + x + 1) (a \u2013 x \u2013 1)                               <\/strong><br \/><strong>(d) none of these<br \/><\/strong><strong>Solution:<br \/><\/strong>a<sup>2<\/sup> \u2013 1- 2x \u2013 x<sup>2<br \/><\/sup>\u21d2 a<sup>2<\/sup> \u2013 (1 + 2x + x<sup>2<\/sup>)<br \/>= (a)<sup>2<\/sup> \u2013 (1 + x)<sup>2<\/sup><br \/>= (a + 1 + x) (a \u2013 1 \u2013 x)                        <strong> (c)<\/strong><\/p>\n<p>Yahan difference of squares formula use kiya gaya hai: a\u00b2 &#8211; b\u00b2 = (a + b)(a &#8211; b). Pehle expression ko perfect square banaya, phir formula apply kiya.<\/p>\n<p><strong>Question 9.<br \/><\/strong><strong>The factors of x<sup>4<\/sup> + x<sup>2<\/sup> + 25 are<\/strong><br \/><strong>(a) (x<sup>2<\/sup> + 3x + 5) (x<sup>2<\/sup> \u2013 3x + 5)                      <\/strong><br \/><strong>(b) (x<sup>2<\/sup> + 3x + 5) (x<sup>2<\/sup> + 3x \u2013 5)<\/strong><br \/><strong>(c) (x<sup>2<\/sup> + x + 5) (x<sup>2<\/sup> \u2013 x + 5)                           <\/strong><br \/><strong>(d) none of these<br \/><\/strong><strong>Solution:<br \/><\/strong>x<sup>4<\/sup> + x<sup>2<\/sup> + 25 = x<sup>4<\/sup> + 25 +x<sup>2<br \/><\/sup>= (x<sup>2<\/sup>)<sup>2<\/sup> + (5)<sup>2<\/sup> + 2 x x<sup>2<\/sup> x 5- 9x<sup>2<br \/><\/sup>= (x<sup>2<\/sup> + 5)<sup>2<\/sup> \u2013 (3x)<sup>2<br \/><\/sup>= (x<sup>2<\/sup> + 5 + 3x) (x<sup>2<\/sup> + 5 \u2013 3x)<br \/>= (x<sup>2<\/sup> + 3x + 5) (x<sup>2<\/sup> \u2013 3x + 5)                 <strong>(a)<\/strong><\/p>\n<p>Is question mein smart technique use ki gayi hai. Expression ko complete square banane ke liye middle term add aur subtract kiya, phir difference of squares apply kiya.<\/p>\n<p><strong>Question 10.<br \/><\/strong><strong>The factors of x<sup>2<\/sup> + 4y<sup>2<\/sup> + 4y \u2013 4xy \u2013 2x \u2013 8 are<\/strong><br \/><strong>(a) (x \u2013 2y \u2013 4) (x \u2013 2y + 2)                            <\/strong><br \/><strong>(b)  (x \u2013 y  +   2) (x \u2013 4y \u2013 4)<\/strong><br \/><strong>(c) (x + 2y \u2013 4) (x + 2y + 2)                         <\/strong><br \/><strong>(d)    none of these<\/strong><br \/><strong>Solution:<br \/><\/strong>x<sup>2<\/sup> + 4y<sup>2<\/sup> + 4y \u2013 4xy \u2013 2x \u2013 8<br \/>\u21d2  x<sup>2<\/sup> + 4y + 4y \u2013 4xy \u2013 2x \u2013 8<br \/>= (x)<sup>2<\/sup> + (2y)<sup>2<\/sup>\u2013 2 x x x 2y + 4y-2x-8<br \/>= (x \u2013 2y)<sup>2<\/sup> \u2013 (2x \u2013 4y) \u2013 8<br \/>= (x \u2013 2y)<sup>2<\/sup> \u2013 2 (x \u2013 2y) \u2013 8<br \/>Let x \u2013 2y = a, then<br \/>a<sup>2<\/sup>\u2013 2a \u2013 8 = a<sup>2<\/sup>\u2013 4a + 2a \u2013 8<br \/>= a(a \u2013 4) + 2(a \u2013 4)<br \/>= (a-4) (a + 2)<br \/>= (x<sup>2<\/sup> -2y-4) (x<sup>2<\/sup> -2y + 2)                    <strong>   (a)<\/strong><\/p>\n<p>Substitution method ka use karke complex expressions ko simple bana sakte hain. Yahan x &#8211; 2y = a rakha to quadratic equation mil gaya.<\/p>\n<p><strong>Question 11.<br \/><\/strong><strong>The factors of x<sup>3<\/sup> \u2013 7x + 6 are<\/strong><br \/><strong>(a) x(x \u2013 6) (x \u2013 1)                                           <\/strong><br \/><strong>(b) (x<sup>2<\/sup> \u2013 6) (x \u2013 1)<\/strong><br \/><strong>(c) (x + 1) (x + 2) (x \u2013 3)                               <\/strong><br \/><strong>(d) (x \u2013 1) (x + 3) (x \u2013 2)<\/strong><br \/><strong>Solution:<br \/><\/strong>x<sup>3 <\/sup>-7x + 6= x<sup>3<\/sup>-1-7x + 7<br \/>= (x \u2013 1) (x<sup>2<\/sup> + x + 1) \u2013 7(x \u2013 1)<br \/>= (x \u2013 1) (x<sup>2<\/sup> + x + 1 \u2013 7)<br \/>= (x \u2013 1) (x<sup>2<\/sup> + x \u2013 6)<br \/>= (x \u2013 1) [x<sup>2<\/sup> + 3x \u2013 2x \u2013 6]<br \/>= (x \u2013 1) [x(x + 3) \u2013 2(x + 3)]<br \/>= (x \u2013 1) (x+ 3) (x \u2013 2)                    <strong>       (d)<\/strong><\/p>\n<p>Cubic expressions ko factorize karne ke liye rational root theorem use kar sakte hain. Pehle possible rational roots check karo, phir synthetic division ya grouping method apply karo.<\/p>\n<p><strong>Question 12.<br \/><\/strong><strong>The expression x<sup>4<\/sup> + 4 can be factorized as<\/strong><br \/><strong>(a) (x<sup>2<\/sup> + 2x + 2) (x<sup>2<\/sup> \u2013 2x + 2)                       <\/strong><br \/><strong>(b) (x<sup>2<\/sup> + 2x + 2) (x<sup>2<\/sup> + 2x \u2013 2)<\/strong><br \/><strong>(c) (x<sup>2<\/sup> \u2013 2x \u2013 2) (x<sup>2<\/sup> \u2013 2x + 2)                         <\/strong><br \/><strong>(d) (x<sup>2<\/sup> + 2) (x<sup>2<\/sup> \u2013 2)<br \/><\/strong><strong>Solution:<br \/><\/strong>x<sup>4<\/sup> + 4 = x<sup>4<\/sup> + 4 + 4x<sup>2<\/sup> \u2013 4x<sup>2<\/sup>                (Adding and subtracting 4x<sup>2<\/sup>)<br \/>= (x<sup>2<\/sup>)<sup>2<\/sup> + (2)<sup>2<\/sup> + 2 x x<sup>2<\/sup> x 2 \u2013 (2x)<sup>2<br \/><\/sup>= (x<sup>2<\/sup> + 2)<sup>2<\/sup> \u2013 (2x)<sup>2<br \/><\/sup>= (x<sup>2<\/sup> + 2 + 2x) (x<sup>2<\/sup> + 2 \u2013 2x)                {\u2235 a<sup>2<\/sup> \u2013 b<sup>2<\/sup> = (a + b) (a \u2013 b)}<br \/>= (x<sup>2<\/sup> + 2x + 2) (x<sup>2<\/sup> \u2013 2x + 2)                 <strong> (a)<\/strong><\/p>\n<p>Sophie Germain identity ka use kiya gaya hai: a\u2074 + 4b\u2074 = (a\u00b2 + 2ab + 2b\u00b2)(a\u00b2 &#8211; 2ab + 2b\u00b2). Ye advanced factorization technique hai.<\/p>\n<p><strong>Question 13.<br \/><\/strong><strong>If 3x = a + b + c, then the value of (x \u2013 a)<sup>3<\/sup> + (x \u2013    bf + (x \u2013 cf \u2013 3(x \u2013 a) (x \u2013 b) (x \u2013 c) is<\/strong><br \/><strong>(a) a + b + c                                                <\/strong><br \/><strong>(b) (a \u2013 b) {b \u2013 c) (c \u2013 a)<\/strong><br \/><strong>(c) 0                                                                  <\/strong><br \/><strong>(d) none of these<br \/><\/strong><strong>Solution:<br \/><\/strong>3x = a + b + c                                                                      .<br \/>\u21d2 3x-a-b-c = 0<br \/>Now, (x \u2013 a)<sup>3<\/sup>+ (x \u2013 b)<sup>3<\/sup> + (x \u2013 c)<sup>3 <\/sup>\u2013 3(x \u2013 a) (x -b)  (x \u2013 c)<br \/>= {(x \u2013 a) + (x \u2013 b) + (x \u2013 c)} {(x \u2013 a)<sup>2<\/sup> + (x \u2013 b)<sup>2 <\/sup>+ (x \u2013 c)<sup>2<\/sup>  \u2013 (x \u2013 a) (x \u2013 b) (x \u2013 b) (x \u2013 c) \u2013 (x \u2013 c) (x \u2013 a)}<br \/>= (x \u2013 a + x \u2013 b + x \u2013 c) {(x \u2013 a)<sup>2<\/sup> + (x \u2013 b)<sup>2  <\/sup>+ (x \u2013 c)<sup>2<\/sup> \u2013 (x \u2013 a) (x \u2013 b) \u2013 (x \u2013 b) (x \u2013 c) \u2013 (x \u2013 c) (x \u2013 a)}<br \/>= (3x \u2013 a \u2013 b -c) {(x \u2013 a)<sup>2<\/sup> + (x -b)<sup>2<\/sup>+ (x \u2013 c)<sup>2<\/sup> \u2013 (x \u2013 a) (x \u2013 b) \u2013 (x \u2013 b) (x \u2013 c) \u2013 (x \u2013 c) (x \u2013 a)}<br \/>But 3x-a-b-c = 0, then<br \/>= 0 x {(x \u2013 a)<sup>2<\/sup> + (x \u2013 b)<sup>2<\/sup> + (x \u2013 c)<sup>2<\/sup> \u2013 (x \u2013 a) (x \u2013 b) \u2013 (x \u2013 b) (x \u2013 c) \u2013 (x \u2013 c) (x \u2013 a)}<br \/>= 0                                                        <strong> (c)<\/strong><\/p>\n<p>Ye question sum of cubes identity aur given condition ka clever use dikhata hai. Jab sum zero hota hai to expression simplify ho jata hai.<\/p>\n<p><strong>Question 14.<br \/><\/strong><strong>If (x + y)<sup>3<\/sup> \u2013 (x \u2013 y)<sup>3<\/sup> \u2013 6y(x<sup>2<\/sup> \u2013 y<sup>2<\/sup>) = ky<sup>2<\/sup>, then k =<\/strong><br \/><strong>(a) 1                                   <\/strong><br \/><strong>(b) 2                                <\/strong><br \/><strong>(c) 4                                     <\/strong><br \/><strong>(d) 8<br \/><\/strong><strong>Solution:<br \/><\/strong>(x + y)<sup>3<\/sup> \u2013 (x \u2013 y)<sup>3<\/sup> \u2013 6y(x<sup>2<\/sup> \u2013 y<sup>2<\/sup>) = ky<sup>2<\/sup><sup><br \/><\/sup>LHS = (x + y)<sup>3<\/sup> \u2013 (x \u2013 y)<sup>3<\/sup> \u2013 3 x (x + y) (x \u2013 y) [x + y \u2013 x + y]<br \/>= (x+y-x + y)<sup>3<\/sup>       {\u2235 a<sup>3<\/sup> \u2013 b<sup>3<\/sup> \u2013 3ab (a \u2013 b) = a<sup>3<\/sup> \u2013 b<sup>3<\/sup>}<br \/>= (2y)<sup>3<\/sup> = 8y<sup>3<br \/><\/sup>Comparing with ky<sup>3<\/sup>, k = 8                  <strong>   (d)<\/strong><\/p>\n<p>Is question mein algebraic manipulation aur identity ka use karke value of k find kiya gaya hai. Coefficient comparison ka method use kiya.<\/p>\n<p><strong>Question 15.<br \/><\/strong><strong>If x<sup>3<\/sup> \u2013 3x<sup>2<\/sup> + 3x \u2013 7 = (x + 1) (ax<sup>2<\/sup> + bx + c), then a + b + c =<\/strong><br \/><strong>(a) 4                                   <\/strong><br \/><strong>(b) 12                             <\/strong><br \/><strong>(c) -10                                 <\/strong><br \/><strong>(d) 3<br \/><\/strong><strong>Solution:<br \/><\/strong>x<sup>3<\/sup> \u2013 3x<sup>2<\/sup> + 3x + 7 = (x + 1) (ax<sup>2<\/sup> + bx + c)<br \/>= ax<sup>3<\/sup> + bx<sup>2<\/sup> + cx + ax<sup>2<\/sup> + bx + c<br \/>x<sup>3<\/sup> \u2013 3x<sup>2<\/sup> + 3x \u2013 7 = ax<sup>3<\/sup> + (b + a)<sup>2<\/sup> + (c + b)x + c<br \/>Comparing the coefficient,<br \/>a = 1<br \/>b + a = -3 \u21d2 b+1=-3 \u21d2 b = -3-1=-4<br \/>c + b = 3 \u21d2 c- 4 = 3 \u21d2 c = 3 + 4 = 7<br \/>a + b + c = 1- 4 + 7 = 8- 4 = 4          <strong>   (a)<\/strong><\/p>\n<p>Polynomial division aur coefficient comparison ka method use karke unknown coefficients find kiye gaye hain. Ye technique algebraic equations solve karne mein useful hai.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"chapter-5-factorization-techniques-overview\"><\/span><span class=\"ez-toc-section\" id=\"chapter-5-factorization-techniques-overview\"><\/span><strong>Chapter 5 Factorization Techniques Overview<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>RD Sharma Class 9 Chapter 5 mein different types of factorization techniques cover kiye gaye hain jo students ke liye fundamental hain. Ye techniques algebra ki strong foundation banane ke liye zaroori hain.<\/p>\n<p><strong>Main Factorization Methods:<\/strong><\/p>\n<ul>\n<li><strong>Common Factor Method:<\/strong> Sabse basic method hai jahan common factors ko bahar nikala jata hai<\/li>\n<li><strong>Grouping Method:<\/strong> Terms ko groups mein divide karke factorize karte hain<\/li>\n<li><strong>Difference of Squares:<\/strong> a\u00b2 &#8211; b\u00b2 = (a+b)(a-b) identity use karte hain<\/li>\n<li><strong>Perfect Square Trinomials:<\/strong> a\u00b2 \u00b1 2ab + b\u00b2 = (a \u00b1 b)\u00b2 form identify karte hain<\/li>\n<li><strong>Sum and Difference of Cubes:<\/strong> a\u00b3 \u00b1 b\u00b3 ke special formulas use karte hain<\/li>\n<li><strong>Substitution Method:<\/strong> Complex expressions ko simple variables se replace karte hain<\/li>\n<\/ul>\n<p>Har method ka apna specific use case hai. Students ko ye samajhna chahiye ki kab kaunsa method apply karna hai. Practice ke saath ye decision making improve hoti hai.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"board-exam-importance-and-weightage\"><\/span><span class=\"ez-toc-section\" id=\"board-exam-importance-and-weightage\"><\/span><strong>Board Exam Importance and Weightage<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>CBSE Board Exam 2026 mein factorization ka significant weightage hai. Algebra section mein ye topic 15-20 marks ka contribute karta hai. Direct questions ke alawa, geometry aur coordinate geometry mein bhi factorization techniques use hote hain.<\/p>\n<p><strong>Expected Question Types in Board Exam:<\/strong><\/p>\n<ul>\n<li>2-3 marks ke short answer questions<\/li>\n<li>4-5 marks ke long answer questions with multiple parts<\/li>\n<li>Application based problems jahan factorization use karni padti hai<\/li>\n<li>Proof based questions where factorization helps in simplification<\/li>\n<\/ul>\n<p>Students ko <a href=\"https:\/\/cbse.gov.in\" rel=\"noopener\" target=\"_blank\">CBSE official website<\/a> regularly check karna chahiye latest updates ke liye. Sample papers aur marking schemes download kar sakte hain preparation ke liye.<\/p>\n<p>Most important exercises for board exam preparation:<\/p>\n<ul>\n<li>Exercise 5.1: Basic factorization methods<\/li>\n<li>Exercise 5.3: Advanced identities and applications<\/li>\n<li>MCQ section: Quick problem solving skills<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"difficulty-level-progression\"><\/span><span class=\"ez-toc-section\" id=\"difficulty-level-progression\"><\/span><strong>Difficulty Level Progression<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>RD Sharma solutions mein difficulty level gradually increase hoti hai jo students ke learning curve ke according designed hai.<\/p>\n<p><strong>Basic Level (Questions 1-5):<\/strong><\/p>\n<p>Ye questions simple identities aur basic factorization techniques cover karte hain. Students ko pehle ye master karna chahiye before moving to advanced topics. Common mistakes avoid karne ke liye step-by-step approach follow karna important hai.<\/p>\n<p><strong>Moderate Level (Questions 6-10):<\/strong><\/p>\n<p>Is level mein mixed techniques use karni padti hain. Multiple methods combine karne ke questions aate hain. Substitution method aur algebraic manipulation skills develop hoti hain.<\/p>\n<p><strong>Advanced Level (Questions 11-15):<\/strong><\/p>\n<p>Complex expressions aur higher degree polynomials ke questions hain. Ye questions competitive exams ke liye bhi useful hain. Critical thinking aur pattern recognition skills develop karte hain.<\/p>\n<p><strong>Tips for Maximum Benefit:<\/strong><\/p>\n<ul>\n<li>NCERT concepts pehle clear karo, phir RD Sharma practice karo<\/li>\n<li>Har method ke liye separate practice sessions rakho<\/li>\n<li>Mistakes ko note karo aur revise karte raho<\/li>\n<li>Time management skills develop karo through regular practice<\/li>\n<\/ul>\n<p>Regular practice se confidence build hoti hai aur exam mein better performance mil sakti hai. Students ko daily practice routine maintain karna chahiye consistent improvement ke liye.<\/p>\n<p>This is the complete blog on RD Sharma Class 9 Solutions Chapter 5 MCQS. To know more about the <a href=\"https:\/\/cbse.gov.in\/\" rel=\"noopener\" target=\"_blank\">CBSE<\/a> Class 9 Maths exam, ask in the comments.<\/p>\n<div class=\"related-articles\" style=\"background:#fff3e0;padding:20px;border-left:4px solid #ff9800;margin:24px 0;border-radius:4px;\">\n<h3 style=\"margin:0 0 12px;color:#e65100;\"><span class=\"ez-toc-section\" id=\"you-may-also-like\"><\/span>You May Also Like<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul style=\"list-style:none;margin:0;padding:0;\">\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 RD Sharma Solutions<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/rd-sharma-solutions\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 Maths Solutions<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/cbse\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 CBSE Preparation<\/a><\/li>\n<li style=\"margin-bottom:8px;\"><a href=\"https:\/\/www.kopykitab.com\/blog\/category\/exam-preparation\/\" style=\"color:#1565c0;text-decoration:none;font-weight:500;\">\u2192 Exam Preparation Guide<\/a><\/li>\n<\/ul>\n<\/div>\n<div class=\"cta-box\" style=\"background:linear-gradient(135deg,#e8f5e9,#c8e6c9);padding:24px;border-radius:8px;margin:24px 0;text-align:center;border:1px solid #a5d6a7;\">\n<h3 style=\"margin:0 0 8px;color:#2e7d32;\"><span class=\"ez-toc-section\" id=\"explore-study-materials\"><\/span>Explore Study Materials<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"margin:0 0 16px;color:#333;\">Get comprehensive study materials, practice tests, and expert guides for your exam preparation.<\/p>\n<p><a href=\"https:\/\/www.kopykitab.com\/competitive-exam-books\" style=\"display:inline-block;background:#2e7d32;color:#fff;padding:12px 32px;border-radius:6px;text-decoration:none;font-weight:600;\">Browse Study Materials \u2192<\/a>\n<\/div>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"faqs-on-RD-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><strong>FAQs on RD Sharma Class 9 Solutions Chapter 5 MCQS<\/strong><span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div class=\"rank-math-block\" id=\"rank-math-faq\">\n<div class=\"rank-math-list\">\n<div class=\"rank-math-list-item\" id=\"faq-question-1631098651580\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"how-many-questions-exist-in-rd-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"how-many-questions-exist-in-RD-sharma-class-9-solutions-chapter-5-mcqs\"><\/span>How many questions exist in RD Sharma Class 9 Solutions Chapter 5 MCQs?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>There are 15 questions in RD Sharma Class 9 Solutions Chapter 5 MCQs. Ye questions different difficulty levels mein arranged hain jo students ko gradual learning experience provide karte hain.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-1631098669862\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-rd-sharma-class-9-solutions-chapter-5-mcqs\"><\/span><span class=\"ez-toc-section\" id=\"is-it-even-beneficial-to-study-RD-sharma-class-9-solutions-chapter-5-mcqs\"><\/span>Is it even beneficial to study RD Sharma Class 9 Solutions Chapter 5 MCQs?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>Yes, your preparation will be strengthened with this amazing help book. This book will answer all your questions. RD Sharma solutions comprehensive coverage provide karte hain jo CBSE syllabus ke according designed hain. Ye MCQs quick revision aur concept testing ke liye perfect hain.<\/p>\n<\/div>\n<\/div>\n<div class=\"rank-math-list-item\" id=\"faq-question-1631098705565\">\n<h3 class=\"rank-math-question\"><span class=\"ez-toc-section\" id=\"are-the-solutions-rd-sharma-class-9-solutions-chapter-5-mcqs-relevant\"><\/span><span class=\"ez-toc-section\" id=\"are-the-solutions-RD-sharma-class-9-solutions-chapter-5-mcqs-relevant\"><\/span>Are the solutions RD Sharma Class 9 Solutions Chapter 5 MCQs relevant?<span class=\"ez-toc-section-end\"><\/span><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer\">\n<p>The solutions are relevant as the subject matter experts design them. Ye solutions 2026 CBSE syllabus ke according updated hain aur board exam pattern follow karte hain. Step-by-step explanations se concepts clear ho jate hain.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Last Updated: May 02, 2026 | This article has been updated with the latest information for 2026. Key Takeaways Access answers of RD Sharma Class 9 Solutions Chapter 5 MCQS Chapter 5 Factorization Techniques Overview Board Exam Importance and Weightage Difficulty Level Progression Read more: RD Sharma \u2014 Complete Guide RD Sharma Class 9 Solutions &#8230; <a title=\"RD Sharma Class 9 Solutions: Complete Guide [2026]\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-5-mcqs\/\" aria-label=\"More on RD Sharma Class 9 Solutions: Complete Guide [2026]\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":125629,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[61598,115468],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125485"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125485"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125485\/revisions"}],"predecessor-version":[{"id":575269,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125485\/revisions\/575269"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125629"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125485"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125485"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125485"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}