{"id":125251,"date":"2023-09-13T13:39:00","date_gmt":"2023-09-13T08:09:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125251"},"modified":"2023-11-13T12:05:29","modified_gmt":"2023-11-13T06:35:29","slug":"rd-sharma-class-10-solutions-chapter-2-vsaqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/","title":{"rendered":"RD Sharma Class 10 Solutions Chapter 2 VSAQS (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125265\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-2-VSAQS.jpg\" alt=\"RD Sharma Class 10 Solutions Chapter 2 VSAQs\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-2-VSAQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-10-Solutions-Chapter-2-VSAQS-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 10 Solutions Chapter 2 VSAQs:&nbsp;<\/strong>Students can download the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-polynomials\/\"><strong>RD Sharma Class 10 Solutions Chapter 2<\/strong><\/a> VSAQs PDF to learn how to solve the questions in this exercise correctly. Students wishing to brush up their concepts can check the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-for-maths\/\"><strong>RD Sharma Solutions Class 10<\/strong><\/a>.<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d39530dfd1b\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d39530dfd1b\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/#access-rd-sharma-class-10-solutions-chapter-2-vsaqs-pdf\" title=\"Access RD Sharma Class 10 Solutions Chapter 2 VSAQs PDF\">Access RD Sharma Class 10 Solutions Chapter 2 VSAQs PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/#faqs-on-rd-sharma-class-10-solutions-chapter-2-vsaqs\" title=\"FAQs on RD Sharma Class 10 Solutions Chapter 2 VSAQs\">FAQs on RD Sharma Class 10 Solutions Chapter 2 VSAQs<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/#where-can-i-download-rd-sharma-class-10-solutions-chapter-2-vsaqs-free-pdf\" title=\"Where can I download RD Sharma Class 10 Solutions Chapter 2 VSAQs free PDF?\">Where can I download RD Sharma Class 10 Solutions Chapter 2 VSAQs free PDF?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/#what-are-the-benefits-of-using-rd-sharma-class-10-solutions-chapter-2-vsaqs\" title=\"What are the benefits of using RD Sharma Class 10 Solutions Chapter 2 VSAQs?\">What are the benefits of using RD Sharma Class 10 Solutions Chapter 2 VSAQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/#is-it-required-to-remember-all-of-the-questions-in-rd-sharma-class-10-solutions-chapter-2-vsaqs\" title=\"Is it required to remember all of the questions in RD Sharma Class 10 Solutions Chapter 2 VSAQs?\">Is it required to remember all of the questions in RD Sharma Class 10 Solutions Chapter 2 VSAQs?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-rd-sharma-class-10-solutions-chapter-2-vsaqs-pdf\"><\/span>Access RD Sharma Class 10 Solutions Chapter 2 VSAQs PDF<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Question 1.<\/strong><br>Define a polynomial with real coefficients.<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125353\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/3c.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"325\" height=\"111\"><\/p>\n<p><strong>Question 2.<\/strong><br>Define the degree of a polynomial.<br><strong>Solution:<\/strong><br>The exponent of the highest degree term in a polynomial is known as its degree. A polynomial of degree O is called a constant polynomial.<\/p>\n<p><strong>Question 3.<\/strong><br>Write the standard form of a linear polynomial with real coefficients.<br><strong>Solution:<\/strong><br>ax + b is the standard form of a linear polynomial with real coefficients and a \u2260 0<\/p>\n<p><strong>Question 4.<\/strong><br>Write the standard form of a quadratic polynomial with real coefficients.<br><strong>Solution:<\/strong><br>ax<sup>2<\/sup> + bx + c is a standard form of a quadratic polynomial with real coefficients and a \u2260 0.<\/p>\n<p><strong>Question 5.<\/strong><br>Write the standard form of a cubic polynomial with real coefficients.<br><strong>Solution:<\/strong><br>ax<sup>3<\/sup>&nbsp;+ bx<sup>2<\/sup> + cx + d is a standard form of the cubic polynomial with real coefficients and a \u2260 0.<\/p>\n<p><strong>Question 6.<\/strong><br>Define the value of a polynomial at a point.<br><strong>Solution:<\/strong><br>If f(x) is a polynomial and a is any real number then the real number obtained by replacing x by \u03b1 in f(x) is called the value of f(x) at x = \u03b1 and is denoted by f(\u03b1).<\/p>\n<p><strong>Question 7.<\/strong><br>Define zero of a polynomial.<br><strong>Solution:<\/strong><br>A real number a is a zero of a polynomial f(x) if f(\u03b1) = 0.<\/p>\n<p><strong>Question 8.<\/strong><br>The sum and product of the zeros of a quadratic polynomial are \u2013 12 and -3 respectively. What is the quadratic polynomial?<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125352\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/3b.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"350\" height=\"182\"><\/p>\n<p><strong>Question 9.<\/strong><br>Write the family of quadratic polynomials having \u2013&nbsp;14&nbsp;and 1 as its zeros.<br><strong>Solution:<\/strong><br><img class=\"alignnone  wp-image-125350\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/3a.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"355\" height=\"252\"><\/p>\n<p><strong>Question 10.<\/strong><br>If the product of zeros of the quadratic polynomial f(x) = x<sup>2<\/sup>&nbsp;\u2013 4x + k is 3, find the value of k.<br><strong>Solution:<\/strong><br>We know that a quadratic polynomial x<sup>2<\/sup>&nbsp;\u2013 (sum of zeros) x + product of zeros<br>In the given polynomial f(x) = x<sup>2<\/sup>&nbsp;\u2013 4x + k is the product of zeros which is equal to 3<br>k = 3<\/p>\n<p><strong>Question 11.<\/strong><br>If the sum of the zeros of a quadratic polynomial f(x) = kx<sup>2<\/sup>&nbsp;\u2013 3x + 5 is 1, write the value of k.<br><strong>Solution:<\/strong><br>f (x) = kx<sup>2<\/sup>&nbsp;\u2013 3x + 5<br>Here a = k, b = -3, c = 5<br><img class=\"alignnone size-full wp-image-125349\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2e.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"299\" height=\"112\"><\/p>\n<p><strong>Question 12.<\/strong><br>In the figure, the graph of a polynomial p (x) is given. Find the zeros of the polynomial.<br><img class=\"alignnone size-full wp-image-125347\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2d.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"310\" height=\"263\"><br><strong>Solution:<\/strong><br>The graph of the given polynomial meets the x-axis at -1 and -3<br>Zero will be -1 and -3<br>Zero of a polynomial is 3<\/p>\n<p><strong>Question 13.<\/strong><br>The graph of a polynomial y = f(x) is given below. Find the number of real zeros of f (x).<br><img class=\"alignnone size-full wp-image-125346\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2c.png\" alt=\"2c\" width=\"296\" height=\"276\"><br><strong>Solution:<\/strong><br>The curve touches the x-axis at one point and also intersects at one point So the number of zeros will be 3, two equal, and one distinct<\/p>\n<p><strong>Question 14.<\/strong><br>The graph of the polynomial f(x) = ax<sup>2<\/sup>&nbsp;+ bx + c is as shown below (in the figure) write the signs of \u2018a\u2019 and b<sup>2<\/sup>&nbsp;\u2013 4ac.<br><img class=\"alignnone size-full wp-image-125343\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2b.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"280\" height=\"188\"><br><strong>Solution:<\/strong><br>The shape of the parabola is up to word a &gt; 0<br>and b<sup>2<\/sup>&nbsp;\u2013 4ac &gt;0 i.e., both are positive.<\/p>\n<p><strong>Question 15.<\/strong><br>The graph of the polynomial f(x) = ax<sup>2<\/sup>&nbsp;+ bx + c is as shown in the figure write the value of b<sup>2<\/sup>&nbsp;\u2013 4ac and the number of real zeros of f(x).<br><img class=\"alignnone size-full wp-image-125341\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/2a.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"293\" height=\"236\"><br><strong>Solution:<\/strong><br>The curve parabola touches the x-axis at one point<br>It has two equal zeros<br>b<sup>2<\/sup>&nbsp;\u2013 4ac = 0<\/p>\n<p><strong>Question 16.<\/strong><br>In&nbsp;<strong>Q. No. 14<\/strong>, write the sign of c<br><strong>Solution:<\/strong><br>The mouth of a parabola is upward and intersect the y-axis above the x-axis<br>c &gt; 0<\/p>\n<p><strong>Question 17.<\/strong><br>In&nbsp;<strong>Q. No. 15<\/strong>, write the sign of c.<br><strong>Solution:<\/strong><br>The mouth of the parabola is downward and intersects the y-axis below the x-axis<br>c &lt; 0<\/p>\n<p><strong>Question 18.<\/strong><br>The graph of a polynomial f (x) is as shown in the figure. Write the number of real zeros of f (x).<br><img class=\"alignnone size-full wp-image-125339\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1j.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"325\" height=\"277\"><br><strong>Solution:<\/strong><br>The curves touch the x-axis at two distinct point<br>It has a pair of two equal zeros i.e., it has 4 real zeros<\/p>\n<p><strong>Question 19.<\/strong><br>If x = 1, is a zero of the polynomial f(x) = x<sup>3<\/sup>&nbsp;\u2013 2x<sup>2<\/sup>&nbsp;+ 4x + k, write the value of k.<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125337\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1i.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"258\" height=\"145\"><\/p>\n<p><strong>Question 20.<\/strong><br>State division algorithm for polynomials.<br><strong>Solution:<\/strong><br>If f(x) is a polynomial and g (x) is a non zero polynomial, there exist two polynomials q (x) and r (x) such that<br>f(x) = g (x) x q (x) + r (x)<br>where r (x) = 0 or degree r (x) &lt; degree g (x)<br>This is called division algorithm<\/p>\n<p><strong>Question 21.<\/strong><br>Give an example of polynomials f(x), g (x), q (x) and r (x) satisfying f(x) = g (x) . q (x) + r (x), where degree r (x) = 0.<br><strong>Solution:<\/strong><br>f (x) = x<sup>3<\/sup>&nbsp;+ x<sup>2<\/sup>&nbsp;+ x + 4<br>g (x) = x + 1<br>q (x) = x<sup>2<\/sup>&nbsp;+ 1<br>r (x) = 3<br>is an example of f (x) = g (x) x q (x) + r (x)<br>where degree of r (x) is zero.<\/p>\n<p><strong>Question 22.<\/strong><br>Write a quadratic polynomial, a sum of whose zeros is 2\u221a3 and their product is 2.<br><strong>Solution:<\/strong><br>Sum of zeros = 2 \u221a3<br>and product of zeros = 2<br>Quadratic polynomial will be f (x) = x2 \u2013 (sum of zeros) x + product of zeros<br>= x<sup>2<\/sup>&nbsp;\u2013 2 \u221a3 x + 2<\/p>\n<p><strong>Question 23.<\/strong><br>If the fourth-degree polynomial is divided by a quadratic polynomial, write the degree of the remainder.<br><strong>Solution:<\/strong><br>Degree of the given polynomial = 4<br>and degree of divisor = 2<br>The degree of quotient will be 4 \u2013 2 = 2<br>and degree of the remainder will be less than 2 In other words equal to or less than one degree<\/p>\n<p><strong>Question 24.<\/strong><br>If f(x) = x<sup>3<\/sup>&nbsp;+ x<sup>2<\/sup>&nbsp;\u2013 ax + b is divisible by x<sup>2<\/sup>&nbsp;\u2013 x, write the value of a and b.<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125334\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1h.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"333\" height=\"313\"><\/p>\n<p><strong>Question 25.<\/strong><br>If a \u2013 b, a and a + b are zeros of the polynomial f(x) = 2x<sup>3<\/sup>&nbsp;\u2013 6x<sup>2<\/sup>&nbsp;+ 5x \u2013 7, write the value of a.<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125332\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1g.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"297\" height=\"261\"><\/p>\n<p><strong>Question 26.<\/strong><br>Write the coefficients of the polynomial p (z) = z<sup>5<\/sup>&nbsp;\u2013 2z<sup>2<\/sup>&nbsp;+ 4.<br><strong>Solution:<\/strong><br>p (z) = z<sup>5<\/sup>&nbsp;+ oz<sup>4<\/sup>&nbsp;+ oz<sup>3<\/sup>&nbsp;\u2013 2z<sup>2<\/sup>&nbsp;+ oz + 4<br>Coefficient of z<sup>5<\/sup>&nbsp;= 1<br>Coefficient of z<sup>4<\/sup>&nbsp;= 0<br>Coefficient of z<sup>3<\/sup>&nbsp;= 0<br>Coefficient of z<sup>2<\/sup>&nbsp;= \u2013 2<br>Coefficient of z = 0<br>Constant = 4<\/p>\n<p><strong>Question 27.<\/strong><br>Write the zeros of the polynomial x<sup>2<\/sup>&nbsp;\u2013 x \u2013 6.&nbsp;<strong>(C.B.S.E. 2008)<\/strong><br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125330\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1f.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"336\" height=\"237\"><\/p>\n<p><strong>Question 28.<\/strong><br>If (x + a) is a factor of 2x<sup>2<\/sup>&nbsp;+ 2ax + 5x + 10, find a.&nbsp;<strong>(C.B.S.E. 2008)<\/strong><br><strong>Solution:<\/strong><br>x + a is a factor of<br><img class=\"alignnone size-full wp-image-125327\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1e.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"329\" height=\"195\"><\/p>\n<p><strong>Question 29.<\/strong><br>For what value of k, -4 is a zero of the polynomial x<sup>2<\/sup> \u2013 x \u2013 (2k + 2)?&nbsp;<strong>(CBSE 2009)<\/strong><br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125325\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1d.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"296\" height=\"300\"><\/p>\n<p><strong>Question 30.<\/strong><br>If 1 is a zero of the polynomial p (x) = ax<sup>2<\/sup>&nbsp;\u2013 3 (a \u2013 1) x \u2013 1, then find the value of a.<br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125322\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1c.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"309\" height=\"324\"><\/p>\n<p><strong>Question 31.<\/strong><br>If \u03b1, \u03b2 are the zeros of a polynomial such that \u03b1 + \u03b2 = -6 and \u03b1 \u03b2 = -4, then write the polynomial.&nbsp;<strong>[CBSE 2010]<\/strong><br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125319\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1b.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"326\" height=\"144\"><\/p>\n<p><strong>Question 32.<\/strong><br>If \u03b1, \u03b2 are the zeros of the polynomial 2y<sup>2<\/sup>&nbsp;+ 7y + 5, write the value of \u03b1 + \u03b2 + \u03b1\u03b2.&nbsp;<strong>[CBSE 2010]<\/strong><br><strong>Solution:<\/strong><br><img class=\"alignnone size-full wp-image-125317\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/1a.png\" alt=\"RD Sharma Class 10 Solutions Chapter 2\" width=\"317\" height=\"221\"><\/p>\n<p><strong>Question 33.<\/strong><br>For what value of k, is 3 a zero of the polynomial 2x<sup>2<\/sup>&nbsp;+ x + k ?&nbsp;<strong>[CBSE 2010]<\/strong><br><strong>Solution:<\/strong><br>3 is a zero of f(x) = 2x<sup>2<\/sup>&nbsp;+ x + k<br>It will satisfy the polynomial<br>f(x) = 0 \u21d2 f(3) = 0<br>Now 2x<sup>2<\/sup>&nbsp;+ x + k = 0<br>=&gt; 2 (3)<sup>2<\/sup>&nbsp;+ 3 + k = 0<br>=&gt; 18 + 3 + k = 0<br>=&gt; 21 + k = 0<br>=&gt; k = -21<\/p>\n<p><strong>Question 34.<\/strong><br>For what value of k, is -3 a zero of the polynomial x<sup>2<\/sup>&nbsp;+ 11x + k ?&nbsp;<strong>[CBSE 2010]<\/strong><br><strong>Solution:<\/strong><br>-3 is a zero of polynomial f(x) = x<sup>2<\/sup>&nbsp;+ 11x + k<br>It will satisfy the polynomial<br>f (x) = 0 =&gt; f(-3) = 0<br>Now x<sup>2<\/sup>&nbsp;+ 11x + k = 0<br>=&gt; (-3)<sup>2<\/sup>+ 11 x (-3) + k = 0<br>\u21d2 9 \u2013 33 + k = 0<br>\u21d2 -24 + k = 0<br>\u21d2 k = 24<\/p>\n<p><strong>Question 35.<\/strong><br>For what value of k, is -2 a zero of the polynomial 3x<sup>2<\/sup>&nbsp;+ 4x + 2k ?<strong>&nbsp;[CBSE 2010]<\/strong><br><strong>Solution:<\/strong><br>-2 is a zero of the polynomial<br>f(x) = 3x<sup>2<\/sup>&nbsp;+ 4x + 2k<br>f(-2) = 0<br>=&gt; 3 (-2)<sup>2<\/sup>&nbsp;+ 4 (-2) + 2k = 0<br>=&gt; 12 \u2013 8 + 2k = 0<br>=&gt; 4 + 2k = 0<br>=&gt; 2k = -4<br>=&gt; k = -2<\/p>\n<p><strong>Question 36.<\/strong><br>If a quadratic polynomial f(x) is factorizable into linear distinct factors, then what is the total number of real and distinct zeros of f (x)?<br><strong>Solution:<\/strong><br>In a quadratic polynomial f(x) its degree is 2 and it can be factorized into two distinct linear factors.<br>f(x) has two distinct zeros<\/p>\n<p><strong>Question 37.<\/strong><br>If a quadratic polynomial f(x) is a square of a linear polynomial, then its two zeros are coincident. (True \/ False)<br><strong>Solution:<\/strong><br>In a quadratic polynomial f(x), it is the square of a linear polynomial It has two zeros that are equal i.e. coincident<br>It is true<\/p>\n<p><strong>Question 38.<\/strong><br>If a quadratic polynomial f(x) is not factorizable into linear factors, then it has no real zero. (True \/ False)<br><strong>Solution:<\/strong><br>A quadratic polynomial f(x) is not factorized into linear factors It has no real zeros It is true<\/p>\n<p><strong>Question 39.<\/strong><br>If f(x) is a polynomial such that f(a) f(b) &lt; 0, then what is the number of zeros lying between a and b?<br><strong>Solution:<\/strong><br>f(x) is a polynomial such that f(a) f(b) &lt; 0<br>At least one of its zeros will be between a and b<\/p>\n<p><strong>Question 40.<\/strong><br>If a graph of quadratic polynomial ax<sup>2<\/sup> + bx + c cuts the positive direction of the y-axis, then what is the sign of c?<br><strong>Solution:<\/strong><br>The graph of quadratic polynomial ax<sup>2<\/sup>&nbsp;+ bx + c cuts positive direction of y-axis Then sign of constant term c will be also positive.<\/p>\n<p><strong>Question 41.<\/strong><br>If the graph of quadratic polynomial ax<sup>2<\/sup> + bx + c cuts the negative direction of the y-axis, then what is the sign of c?<br><strong>Solution:<\/strong><br>The graph of quadratic polynomial ax<sup>2<\/sup> + bx + c cuts the negative side of the y-axis<br>Then the sign of constant term c will be negative.<\/p>\n<p>We have provided complete details of RD Sharma Class 10 Solutions Chapter 2 VSAQs. If you have any queries related to <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\"><strong>CBSE<\/strong><\/a>&nbsp;Class 10, feel free to ask us in the comment section below.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-class-10-solutions-chapter-2-vsaqs\"><\/span>FAQs on RD Sharma Class 10 Solutions Chapter 2 VSAQs<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631087883978\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"where-can-i-download-rd-sharma-class-10-solutions-chapter-2-vsaqs-free-pdf\"><\/span>Where can I download RD Sharma Class 10 Solutions Chapter 2 VSAQs free PDF?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download RD Sharma Class 10 Solutions Chapter 2 VSAQs free PDF from the above article.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631087991856\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-using-rd-sharma-class-10-solutions-chapter-2-vsaqs\"><\/span>What are the benefits of using RD Sharma Class 10 Solutions Chapter 2 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>1. Correct answers according to the last CBSE guidelines and syllabus.<br \/>2. The RD Sharma Class 10 Solutions Chapter 2 VSAQs are written in simple language to assist students in their board examination, &amp; competitive examination preparation.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631088032563\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-it-required-to-remember-all-of-the-questions-in-rd-sharma-class-10-solutions-chapter-2-vsaqs\"><\/span>Is it required to remember all of the questions in RD Sharma Class 10 Solutions Chapter 2 VSAQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, all of the questions in RD Sharma Class 10 Solutions Chapter 2 VSAQs must be learned. These questions may appear on both board exams and class tests. Students will be prepared for their board exams if they learn these questions.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 10 Solutions Chapter 2 VSAQs:&nbsp;Students can download the RD Sharma Class 10 Solutions Chapter 2 VSAQs PDF to learn how to solve the questions in this exercise correctly. Students wishing to brush up their concepts can check the RD Sharma Solutions Class 10. Access RD Sharma Class 10 Solutions Chapter 2 VSAQs &#8230; <a title=\"RD Sharma Class 10 Solutions Chapter 2 VSAQS (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-10-solutions-chapter-2-vsaqs\/\" aria-label=\"More on RD Sharma Class 10 Solutions Chapter 2 VSAQS (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":238,"featured_media":125265,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411,2985,73410],"tags":[3243,9206,73520,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125251"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/238"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125251"}],"version-history":[{"count":5,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125251\/revisions"}],"predecessor-version":[{"id":506730,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125251\/revisions\/506730"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125265"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125251"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125251"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125251"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}