{"id":125186,"date":"2023-09-03T01:08:00","date_gmt":"2023-09-02T19:38:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=125186"},"modified":"2023-11-24T10:34:16","modified_gmt":"2023-11-24T05:04:16","slug":"rd-sharma-class-9-solutions-chapter-4-exercise-4-4","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone wp-image-125228 size-full\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-4-Exercise-4.4.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-4-Exercise-4.4.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-4-Exercise-4.4-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4: <\/strong>You can always clear your doubts and get help in getting good marks in your Class 9 Maths exams with <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Solutions Class 9 Maths<\/a>. It is important to understand everything from the core and you can do it by practicing the questions of <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-4-algebraic-identities\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 4 <\/a> Exercise 4.4.\u00a0\u00a0<\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69d2a28e32451\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69d2a28e32451\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#download-rd-sharma-class-9-solutions-chapter-4-exercise-44-pdf\" title=\"Download RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 PDF\">Download RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 PDF<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#access-answers-of-rd-sharma-class-9-solutions-chapter-4-exercise-44\" title=\"Access answers of RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4\">Access answers of RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#faqs-on-rd-sharma-solutions-class-9-maths-chapter-4-exercise-44\" title=\"FAQs on RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4\">FAQs on RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#how-many-questions-are-there-in-rd-sharma-solutions-for-class-9-maths-chapter-4-exercise-44\" title=\"How many questions are there in RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?\">How many questions are there in RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-4-exercise-44\" title=\"From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4?\">From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/#how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-4-exercise-44\" title=\"How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?\">How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"download-rd-sharma-class-9-solutions-chapter-4-exercise-44-pdf\"><\/span><strong>Download RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 PDF<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><a href=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-4-Ex-4.4.pdf\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4<\/a><\/p>\n<div id=\"example1\" style=\"text-align: justify;\">\u00a0<\/div>\n<p style=\"text-align: justify;\"><style>\n.pdfobject-container { height: 500px;}<br \/>\n.pdfobject { border: 1px solid #666; }<br \/>\n<\/style><\/p>\n<p style=\"text-align: justify;\"><script src=\"https:\/\/www.kopykitab.com\/_utility\/js\/pdfobject.min.js\"><\/script><br \/><script>PDFObject.embed(\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-SHARMA-Solutions-Class-9-Maths-Chapter-4-Ex-4.4.pdf\", \"#example1\");<\/script><\/p>\n<h2><span class=\"ez-toc-section\" id=\"access-answers-of-rd-sharma-class-9-solutions-chapter-4-exercise-44\"><\/span><strong>Access answers of RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Question 1: Find the following products:<\/strong><\/p>\n<p><strong>(i) (3x + 2y)(9x<sup>2<\/sup>\u00a0\u2013 6xy + 4y<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(ii) (4x \u2013 5y)(16x<sup>2<\/sup>\u00a0+ 20xy + 25y<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(iii) (7p<sup>4<\/sup>\u00a0+ q)(49p<sup>8<\/sup>\u00a0\u2013 7p<sup>4<\/sup>q + q<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(iv) (x\/2 + 2y)(x<sup>2<\/sup>\/4 \u2013 xy + 4y<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(v) (3\/x \u2013 5\/y)(9\/x<sup>2<\/sup>\u00a0+ 25\/y<sup>2<\/sup>\u00a0+ 15\/xy)<\/strong><\/p>\n<p><strong>(vi) (3 + 5\/x)(9 \u2013 15\/x + 25\/x<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(vii) (2\/x + 3x)(4\/x<sup>2\u00a0<\/sup>+ 9x<sup>2\u00a0<\/sup>\u2013 6)<\/strong><\/p>\n<p><strong>(viii) (3\/x \u2013 2x<sup>2<\/sup>)(9\/x<sup>2\u00a0<\/sup>+ 4x<sup>4<\/sup>\u00a0\u2013 6x)<\/strong><\/p>\n<p><strong>(ix) (1 \u2013 x)(1 + x + x<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(x) (1 + x)(1 \u2013 x + x<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>(xi) (x<sup>2\u00a0<\/sup>\u2013 1)(x<sup>4<\/sup>\u00a0+ x<sup>2\u00a0<\/sup>+1)<\/strong><\/p>\n<p><strong>(xii) (x<sup>3\u00a0<\/sup>+ 1)(x<sup>6<\/sup>\u00a0\u2013 x<sup>3<\/sup>\u00a0+ 1)<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)<\/strong>\u00a0(3x + 2y)(9x<sup>2<\/sup>\u00a0\u2013 6xy + 4y<sup>2<\/sup>)<\/p>\n<p>= (3x + 2y)[(3x)<sup>2<\/sup>\u00a0\u2013 (3x)(2y) + (2y)<sup>2<\/sup>)]<\/p>\n<p>We know, a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab)<\/p>\n<p>= (3x)<sup>3<\/sup>\u00a0+ (2y)<sup>\u00a03<\/sup><\/p>\n<p>= 27x<sup>3<\/sup>\u00a0+ 8y<sup>3<\/sup><\/p>\n<p><strong>(ii)<\/strong>\u00a0(4x \u2013 5y)(16x<sup>2<\/sup>\u00a0+ 20xy + 25y<sup>2<\/sup>)<\/p>\n<p>= (4x \u2013 5y)[(4x)<sup>2<\/sup>\u00a0+ (4x)(5y) + (5y)<sup>2<\/sup>)]<\/p>\n<p>We know, a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab)<\/p>\n<p>= (4x)<sup>3<\/sup>\u00a0\u2013 (5y)<sup>\u00a03<\/sup><\/p>\n<p>= 64x<sup>3<\/sup>\u00a0\u2013 125y<sup>3<\/sup><\/p>\n<p><strong>(iii)<\/strong>\u00a0(7p<sup>4<\/sup>\u00a0+ q)(49p<sup>8<\/sup>\u00a0\u2013 7p<sup>4<\/sup>q + q<sup>2<\/sup>)<\/p>\n<p>= (7p<sup>4<\/sup>\u00a0+ q)[(7p<sup>4<\/sup>)<sup>2<\/sup>\u00a0\u2013 (7p<sup>4<\/sup>)(q) + (q)<sup>2<\/sup>)]<\/p>\n<p>We know, a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab)<\/p>\n<p>= (7p<sup>4<\/sup>)<sup>3<\/sup>\u00a0+ (q)<sup>\u00a03<\/sup><\/p>\n<p>= 343 p<sup>12<\/sup>\u00a0+ q<sup>3<\/sup><\/p>\n<p><strong>(iv)<\/strong>\u00a0(x\/2 + 2y)(x<sup>2<\/sup>\/4 \u2013 xy + 4y<sup>2<\/sup>)<\/p>\n<p>We know, a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab)<\/p>\n<p>(x\/2 + 2y)(x<sup>2<\/sup>\/4 \u2013 xy + 4y<sup>2<\/sup>)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 Solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-image-1.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 Solution\" \/><\/p>\n<p><strong>(v)<\/strong>\u00a0(3\/x \u2013 5\/y)(9\/x<sup>2<\/sup>\u00a0+ 25\/y<sup>2<\/sup>\u00a0+ 15\/xy)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4\" \/><\/p>\n<p>[Using a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab) ]<\/p>\n<p><strong>(vi)<\/strong>\u00a0(3 + 5\/x)(9 \u2013 15\/x + 25\/x<sup>2<\/sup>)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-solution.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 solution\" \/><\/p>\n<p>[Using: a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab)]<\/p>\n<p><strong>(vii)<\/strong>\u00a0(2\/x + 3x)(4\/x<sup>2\u00a0<\/sup>+ 9x<sup>2\u00a0<\/sup>\u2013 6)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 1\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2020\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 1\" \/><\/p>\n<p>[Using: a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab)]<\/p>\n<p><strong>(viii)<\/strong>\u00a0(3\/x \u2013 2x<sup>2<\/sup>)(9\/x<sup>2\u00a0<\/sup>+ 4x<sup>4<\/sup>\u00a0\u2013 6x)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 1 solution\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question-1.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 1 solution\" \/><\/p>\n<p>[Using : a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab)]<\/p>\n<p><strong>(ix)<\/strong>\u00a0(1 \u2013 x)(1 + x + x<sup>2<\/sup>)<\/p>\n<p>And we know, a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab)<\/p>\n<p>(1 \u2013 x)(1 + x + x<sup>2<\/sup>) can be written as<\/p>\n<p>(1 \u2013 x)[(1<sup>2<\/sup>\u00a0+ (1)(x)+ x<sup>2<\/sup>)]<\/p>\n<p>= (1)<sup>3<\/sup>\u00a0\u2013 (x)<sup>3<\/sup><\/p>\n<p>= 1 \u2013 x<sup>3<\/sup><\/p>\n<p><strong>(x)<\/strong>\u00a0(1 + x)(1 \u2013 x + x<sup>2<\/sup>)<\/p>\n<p>And we know, a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab)]<\/p>\n<p>(1 + x)(1 \u2013 x + x<sup>2<\/sup>) can be written as,<\/p>\n<p>(1 + x)[(1<sup>2<\/sup>\u00a0\u2013 (1)(x) + x<sup>2<\/sup>)]<\/p>\n<p>= (1)<sup>3<\/sup>\u00a0+ (x)<sup>\u00a03<\/sup><\/p>\n<p>= 1 + x<sup>3<\/sup><\/p>\n<p><strong>(xi)<\/strong>\u00a0(x<sup>2\u00a0<\/sup>\u2013 1)(x<sup>4<\/sup>\u00a0+ x<sup>2\u00a0<\/sup>+1) can be written as,<\/p>\n<p>(x<sup>2<\/sup>\u00a0\u2013 1)[(x<sup>2<\/sup>)<sup>2<\/sup>\u00a0\u2013 1<sup>2<\/sup>\u00a0+ (x<sup>2<\/sup>)(1)]<\/p>\n<p>= (x<sup>2<\/sup>)<sup>3<\/sup>\u00a0\u2013 1<sup>3<\/sup><\/p>\n<p>= x<sup>6<\/sup>\u00a0\u2013 1<\/p>\n<p>[using a<sup>3<\/sup>\u00a0\u2013 b<sup>3<\/sup>\u00a0= (a \u2013 b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab) ]<\/p>\n<p><strong>(xii)<\/strong>\u00a0(x<sup>3\u00a0<\/sup>+ 1)(x<sup>6<\/sup>\u00a0\u2013 x<sup>3<\/sup>\u00a0+ 1) can be written as,<\/p>\n<p>(x<sup>3<\/sup>\u00a0+ 1)[(x<sup>3<\/sup>)<sup>2<\/sup>\u00a0\u2013 (x<sup>3<\/sup>)(1) + 1<sup>2<\/sup>]<\/p>\n<p>= (x<sup>3<\/sup>)<sup>\u00a03<\/sup>\u00a0+ 1<sup>3<\/sup><\/p>\n<p>= x<sup>9<\/sup>\u00a0+ 1<\/p>\n<p>[using a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= (a + b)(a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab) ]<\/p>\n<p><strong>Question 2: If x = 3 and y = -1, find the values of each of the following using in identity:<\/strong><\/p>\n<p><strong>(i) (9y<sup>2<\/sup>\u00a0\u2013 4x<sup>2<\/sup>)(81y<sup>4<\/sup>\u00a0+ 36x<sup>2<\/sup>y<sup>2<\/sup>\u00a0+ 16x<sup>4<\/sup>)<\/strong><\/p>\n<p><strong>(ii) (3\/x \u2013 x\/3)(x<sup>2<\/sup>\u00a0\/9 + 9\/x<sup>2<\/sup>\u00a0+ 1)<\/strong><\/p>\n<p><strong>(iii) (x\/7 + y\/3)(x<sup>2<\/sup>\/49 + y<sup>2<\/sup>\/9 \u2013 xy\/21)<\/strong><\/p>\n<p><strong>(iv) (x\/4 \u2013 y\/3)(x<sup>2<\/sup>\/16 + xy\/12 + y<sup>2<\/sup>\/9)<br \/>(v) (5\/x + 5x)(25\/x<sup>2<\/sup>\u00a0\u2013 25 + 25x<sup>2<\/sup>)<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p><strong>(i)<\/strong>\u00a0(9y<sup>2<\/sup>\u00a0\u2013 4x<sup>2<\/sup>)(81y<sup>4<\/sup>\u00a0+ 36x<sup>2<\/sup>y<sup>2<\/sup>\u00a0+ 16x<sup>4<\/sup>)<\/p>\n<p>= (9y<sup>2<\/sup>\u00a0\u2013 4x<sup>2<\/sup>) [(9y<sup>2<\/sup>\u00a0)<sup>\u00a02\u00a0<\/sup>+ 9y<sup>2<\/sup>\u00a0x 4x<sup>2\u00a0<\/sup>+ (4x<sup>2<\/sup>)<sup>\u00a02<\/sup>\u00a0]<\/p>\n<p>= (9y<sup>2<\/sup>\u00a0)<sup>\u00a03\u00a0<\/sup>\u2013 (4x<sup>2<\/sup>)<sup>3<\/sup><\/p>\n<p>= 729 y<sup>6<\/sup>\u00a0\u2013 64 x<sup>6<\/sup><\/p>\n<p>Put x = 3 and y = -1<\/p>\n<p>= 729 \u2013 46656<\/p>\n<p>= \u2013 45927<\/p>\n<p><strong>(ii)<\/strong>\u00a0Put x = 3 and y = -1<\/p>\n<p>(3\/x \u2013 x\/3)(x<sup>2<\/sup>\u00a0\/9 + 9\/x<sup>2<\/sup>\u00a0+ 1)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 2\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question-2.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 2\" \/><\/p>\n<p><strong>(iii)<\/strong>\u00a0Put x = 3 and y = -1<\/p>\n<p>(x\/7 + y\/3)(x<sup>2<\/sup>\/49 + y<sup>2<\/sup>\/9 \u2013 xy\/21)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 3\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2020\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question-3.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 3\" \/><\/p>\n<p><strong>(iv)<\/strong>\u00a0Put x = 3 and y = -1<\/p>\n<p>(x\/4 \u2013 y\/3)(x<sup>2<\/sup>\/16 + xy\/12 + y<sup>2<\/sup>\/9)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 4\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2019\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question-4.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 4\" \/><\/p>\n<p><strong>(v)<\/strong>\u00a0Put x = 3 and y = -1<\/p>\n<p>(5\/x + 5x)(25\/x<sup>2<\/sup>\u00a0\u2013 25 + 25x<sup>2<\/sup>)<\/p>\n<p><img title=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 5\" src=\"https:\/\/cdn1.byjus.com\/wp-content\/uploads\/2020\/10\/rd-sharma-class-9-maths-chapter-4-ex-4-4-question-5.png\" alt=\"RD sharma class 9 maths chapter 4 ex 4.4 question 2 solution part 5\" \/><\/p>\n<p><strong>Question 3: If a + b = 10 and ab = 16, find the value of a<sup>2<\/sup>\u00a0\u2013 ab + b<sup>2<\/sup>\u00a0and a<sup>2<\/sup>\u00a0+ ab + b<sup>2<\/sup>.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>a + b = 10, ab = 16<\/p>\n<p>Squaring, a + b = 10, both sides<\/p>\n<p>(a + b)<sup>2<\/sup>\u00a0= (10)<sup>2<\/sup><\/p>\n<p>a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ 2ab = 100<\/p>\n<p>a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ 2 x 16 = 100<\/p>\n<p>a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ 32 = 100<\/p>\n<p>a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0= 100 \u2013 32 = 68<\/p>\n<p>a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0= 68<\/p>\n<p>Again, a<sup>2<\/sup>\u00a0\u2013 ab + b<sup>2<\/sup>\u00a0= a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0\u2013 ab = 68 \u2013 16 = 52 and<\/p>\n<p>a<sup>2<\/sup>\u00a0+ ab + b<sup>2<\/sup>\u00a0= a<sup>2<\/sup>\u00a0+ b<sup>2<\/sup>\u00a0+ ab = 68 + 16 = 84<\/p>\n<p><strong>Question 4: If a + b = 8 and ab = 6, find the value of a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>.<\/strong><\/p>\n<p><strong>Solution:<\/strong><\/p>\n<p>a + b = 8, ab = 6<\/p>\n<p>Cubing, a + b = 8, both sides, we get<\/p>\n<p>(a + b)<sup>3<\/sup>\u00a0= (8)<sup>3<\/sup><\/p>\n<p>a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0+ 3ab(a + b) = 512<\/p>\n<p>a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0+ 3 x 6 x 8 = 512<\/p>\n<p>a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0+ 144 = 512<\/p>\n<p>a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= 512 \u2013 144 = 368<\/p>\n<p>a<sup>3<\/sup>\u00a0+ b<sup>3<\/sup>\u00a0= 368<\/p>\n<p>This is the complete blog of RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4. To know more about the <a href=\"https:\/\/www.cbse.gov.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> Class 9 Maths exam, ask in the comments.\u00a0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"faqs-on-rd-sharma-solutions-class-9-maths-chapter-4-exercise-44\"><\/span><strong>FAQs on RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1631034263228\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-many-questions-are-there-in-rd-sharma-solutions-for-class-9-maths-chapter-4-exercise-44\"><\/span>How many questions are there in RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>There are 6 questions in\u00a0RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631034322904\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"from-where-can-i-download-the-pdf-of-rd-sharma-solutions-class-9-maths-chapter-4-exercise-44\"><\/span>From where can I download the PDF of RD Sharma Solutions Class 9 Maths Chapter 4 Exercise 4.4?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can find the download link from the above blog.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1631034341921\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"how-much-does-it-cost-to-download-the-pdf-of-rd-sharma-solutions-for-class-9-maths-chapter-4-exercise-44\"><\/span>How much does it cost to download the PDF of RD Sharma Solutions for Class 9 Maths Chapter 4 Exercise 4.4?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>You can download it for free.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4: You can always clear your doubts and get help in getting good marks in your Class 9 Maths exams with RD Sharma Solutions Class 9 Maths. It is important to understand everything from the core and you can do it by practicing the questions of RD &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-4-exercise-4-4\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 4 Exercise 4.4 (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":243,"featured_media":125228,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73411],"tags":[3086,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125186"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/243"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=125186"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125186\/revisions"}],"predecessor-version":[{"id":511875,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/125186\/revisions\/511875"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125228"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=125186"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=125186"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=125186"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}