<\/span><\/h2>\nQuestion 1.
Which one of the following is not a measure of central value?
(a) Mean
(b) Range
(c) Median
(d) Mode
Solution:
Range (b)<\/p>\n
Question 2.
The mean of n observations is\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0. If k is added to each observation, then the new mean is
(a)\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>
(b)\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0+ k
(c)\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0\u2013 k
(d) kX<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>
Solution:
Mean of n observation =\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>
By adding k to each observation the new mean will be\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0+ k (b)<\/p>\nQuestion 3.
The mean of n observations is\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0. If each observation is multiplied by k, the mean of new observations is
(a) kX<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>
(b)\u00a0X<\/span>\u00af\u00af\u00af\u00af\u00af<\/span><\/span>k<\/span><\/span><\/span><\/span><\/span>
(c)\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0+ k
(d)\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0\u2013 k
Solution:
Mean of n observations =\u00a0X<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>
By multiplying each observation by k,
the new mean = kX<\/span>\u00af\u00af\u00af\u00af<\/span><\/span><\/span><\/span><\/span>\u00a0(a)<\/p>\nQuestion 4.
The mean of a set of seven numbers is 81. If one of the numbers is discarded, the mean of the remaining numbers is 78. The value of a discarded number is
(a) 98
(b) 99
(c) 100
(d) 101
Solution:
The mean of 7 numbers = 81
Total = 7 x 81 = 567
By discarding one number, the mean of the remaining 7 \u2013 1 = 6 numbers = 78
Total = 6 x 78 = 468
Discarded number = 567 \u2013 468 = 99 (b)<\/p>\n
Question 5.
For which set of numbers do the mean, median and mode all have the same value?
(a) 2, 2, 2, 2, 4
(b) 1, 3, 3, 3, 5
(c) 1, 1, 2, 5, 6
(d) 1, 1, 1, 2, 5
Solution:
a) In set 2, 2, 2, 2, 4
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q5-24.png\")
Mode = 3 as it comes in maximum times
This set has the mean, median, and mode same (b)<\/p>\n
Question 6.
For the set of numbers 2, 2, 4, 5, and 12, which of the following statements is true?
(a) Mean = Median
(b) Mean > Mode
(c) Mean < Mode
(d) Mode = Median
Solution:
The given set is 2, 2, 4, 5, 12<\/p>\n
Question 6.
For the set of numbers 2, 2, 4, 5, and 12, which of the following statements is true?
(a) Mean = Median
(b) Mean > Mode
(c) Mean < Mode
(d) Mode = Median
Solution:
The given set is 2, 2, 4, 5, 12<\/p>\n
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q6-24.png\")
<\/p>\n
Question 7.
If the arithmetic mean of 7, 5, 13, x and 9 is 10, then the value of x is
(a) 10
(b) 12
(c) 14
(d) 16
Solution:
The arithmetic mean of 7, 5, 13, x, 9 is 10<\/p>\n
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q7-24.png\")
<\/p>\n
Question 8.
If the mean of five observations x, x + 2, x + 4, x + 6, x + 8, is 11, then the mean of first three observations is
(a) 9
(b) 11
(c) 13
(d) none of these
Solution:
Mean = 11
But mean of x, x + 2, x + 4, x+ 6, x + 8<\/p>\n
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q8-24.png\")
<\/p>\n
Question 9.
Mode is
(a) least frequent value
(b) middlemost value
(c) most frequent value
(d) none of these
Solution:
Mode is the most frequent value (c)<\/p>\n
Question 10.
The following is the data of wages per day: 5, 4, 7, 5, 8, 8, 8, 5, 7, 9, 5, 7, 9, 10, 8 The mode of the data is
(a) 7
(b) 5
(c) 8
(d) 10
Solution:
Wages per day
5, 4, 7, 5, 8, 8, 8, 5, 7, 9, 5, 7, 9, 10, 8
=> 4, 5, 5, 5, 5, 7, 7, 7, 8, 8, 8, 8, 9, 9, 10
Here 8 comes in the maximum times
Mode = 8 (c)<\/p>\n
Question 11.
The median of the following data :
is,
(a) 0
(b) -1.5
(c) 2
(d) 3.5
Solution:
Arranging in ascending order,
-3, -3, -1, 0, 2, 2, 2, 5, 5, 5, 5, 6, 6, 6<\/p>\n
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q11-24.png\")
<\/p>\n
Question 12.
The algebraic sum of the deviations of a set of n values from their mean is
(a) 0
(b) n \u2013 1
(c) n
(d) n + 1
Solution:
The algebraic sum of deviation of a set of n values from that mean<\/p>\n
Question 13.
A, B, C are three sets of values of X:
A : 2, 3, 7, 1, 3, 2, 3
B: 7, 5, 9, 12, 5, 3, 8
C: 4, 4, 11, 7 ,2, 3, 4
Which one of the following statements is
correct?
(a) Mean of A = Mode of C
(b) Mean of C = Median of B
(c) Median of B = Mode of A
(d) Mean, Median, and Mode of A are equal.
Solution:
Arranging the sets in ascending order
A{2, 3, 7, 1,3,2,3)
= {1, 2, 2, 3, 3, 3, 7)
B = {7, 5, 9, 12, 5, 3, 8)
= {3, 5, 5, 7, 8, 9, 12)
C = {4, 4, 11,7,2,3,4)
= {2, 3, 4, 4, 4, 7, 11)<\/p>\n
![\"\"](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/q-13-24.png\")
<\/p>\n
Mode = 5 {as it comes max times}
(c) Mean of set C =\u00a0<\/span>2<\/span>+<\/span>3<\/span>+<\/span>4<\/span>+<\/span>4<\/span>+<\/span>4<\/span>+<\/span>7<\/span>+<\/span>11<\/span><\/span>7<\/span><\/span><\/span><\/span><\/span>
=\u00a0<\/span>35<\/span>7<\/span><\/span><\/span><\/span><\/span>\u00a0= 5
Median =\u00a0<\/span>7<\/span>+<\/span>1<\/span><\/span>2<\/span><\/span><\/span><\/span><\/span>\u00a0th =<\/span>8<\/span>2<\/span><\/span><\/span><\/span><\/span>\u00a0=4th term = 4
Mode =4 {as it comes max times}
In set A,mean = median = mode = 3 (d)<\/p>\nQuestion 14.
The empirical relation between mean, mode and median is
(a) Mode = 3 Median \u2014 2 Mean
(b) Mode 2 Median \u2014 3 Mean
(c) Median 3 Mode \u2014 2 Mean
(d) Mean = 3 Median \u20142 Mode
Solution:
The empirical relations between mean, mode
and median is
Mode = 3 Median \u2014 2 Mean (a)<\/p>\n
Question 15.
The mean of a, b, c, d, and e is 28. If the mean of a, c, and e is 24, what is the mean of b and d?
(a) 31
(b) 32
(c) 33
(d) 34
Solution:
Mean of a, b, c, d and e = 28
Total of a, b, c, d and e = 28 x 5 = 140
Mean of a, c and e is = 24
Total of a, c, e = 24 x 3 = 72
Total of b and d = 140 \u2013 72 = 68
Mean =\u00a0<\/span>68<\/span>2<\/span><\/span><\/span><\/span><\/span>\u00a0= 34 (d)<\/p>\nWe have included all the information regarding CBSE<\/a> RD Sharma Class 9 Solutions Chapter 24 MCQS<\/span>. If you have any queries feel free to ask in the comment section.\u00a0<\/span><\/p>\n
![\"RD](\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-24-MCQS.jpg\")
<\/p>\n