{"id":124870,"date":"2023-09-03T06:10:00","date_gmt":"2023-09-03T00:40:00","guid":{"rendered":"https:\/\/www.kopykitab.com\/blog\/?p=124870"},"modified":"2023-11-21T10:32:52","modified_gmt":"2023-11-21T05:02:52","slug":"rd-sharma-class-9-solutions-chapter-20-mcqs","status":"publish","type":"post","link":"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/","title":{"rendered":"RD Sharma Class 9 Solutions Chapter 20 MCQs (Updated for 2024)"},"content":{"rendered":"\n<p><img class=\"alignnone size-full wp-image-125622\" src=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-20-MCQS.jpg\" alt=\"RD Sharma Class 9 Solutions Chapter 20 MCQs\" width=\"1200\" height=\"675\" srcset=\"https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-20-MCQS.jpg 1200w, https:\/\/www.kopykitab.com\/blog\/wp-content\/uploads\/2021\/09\/RD-Sharma-Class-9-Solutions-Chapter-20-MCQS-768x432.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/p>\n<p><strong>RD Sharma Class 9 Solutions Chapter 20 MCQs:\u00a0<\/strong>You can easily download the <a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-solutions-class-9-maths-chapter-20-surface-area-and-volume-of-a-right-circular-cone\/\" target=\"_blank\" rel=\"noopener\">RD Sharma Class 9 Chapter 20 <\/a>MCQs solutions. These solutions are created by our experts and you can easily download them in PDF format. The RD Sharma solutions will benefit you in scoring good marks in Class 9 Maths exams. You can easily keep them for as long as you want. The solutions are explained in a detailed manner.<\/p>\n<ul>\n<li><a href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-for-maths\/\" target=\"_blank\" rel=\"noopener\"><span data-sheets-value=\"{&quot;1&quot;:2,&quot;2&quot;:&quot;RD Sharma Class 9 Maths Solutions&quot;}\" data-sheets-userformat=\"{&quot;2&quot;:4540,&quot;5&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;6&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;7&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;8&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;10&quot;:2,&quot;11&quot;:0,&quot;15&quot;:&quot;Arial&quot;}\">RD Sharma Class 9 Maths Solutions<\/span><\/a><\/li>\n<\/ul>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_47_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"ez-toc-toggle-icon-1\"><label for=\"item-69e8eff02fe59\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;direction:ltr;\"><svg style=\"fill: #000000;color:#000000\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #000000;color:#000000\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input  type=\"checkbox\" id=\"item-69e8eff02fe59\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-visibility-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/#access-rd-sharma-class-9-solutions-chapter-20-mcqs\" title=\"Access RD Sharma Class 9 Solutions Chapter 20 MCQS\">Access RD Sharma Class 9 Solutions Chapter 20 MCQS<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/#faq-rd-sharma-class-9-solutions-chapter-20-mcqs\" title=\"FAQ: RD Sharma Class 9 Solutions Chapter 20 MCQs\">FAQ: RD Sharma Class 9 Solutions Chapter 20 MCQs<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/#can-i-download-rd-sharma-class-9-solutions-chapter-20-mcqs-pdf-free\" title=\"Can I download RD Sharma Class 9 Solutions Chapter 20 MCQs PDF free?\">Can I download RD Sharma Class 9 Solutions Chapter 20 MCQs PDF free?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/#what-are-the-benefits-of-studying-rd-sharma-class-9-solutions-chapter-20-mcqs\" title=\"What are the benefits of studying RD Sharma Class 9 Solutions Chapter 20 MCQs?\">What are the benefits of studying RD Sharma Class 9 Solutions Chapter 20 MCQs?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/#is-rd-sharma-enough-for-class-12-maths\" title=\"Is RD Sharma enough for Class 12 Maths?\">Is RD Sharma enough for Class 12 Maths?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"access-rd-sharma-class-9-solutions-chapter-20-mcqs\"><\/span>Access RD Sharma Class 9 Solutions Chapter 20 MCQS<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Question 1.<br \/>The number of surfaces of a cone has, is<br \/>(a) 1<br \/>(b) 2<br \/>(c) 3<br \/>(d) 4<br \/>Solution:<br \/>The number of surfaces of a cone are 2 (b)<\/p>\n<p>Question 2.<br \/>The area of the curved surface of a cone of radius 2r and slant height\u00a0<span id=\"MathJax-Element-1-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-1\" class=\"math\"><span id=\"MathJax-Span-2\" class=\"mrow\"><span id=\"MathJax-Span-3\" class=\"mfrac\"><span id=\"MathJax-Span-4\" class=\"mn\">1<\/span><span id=\"MathJax-Span-5\" class=\"mn\">2<\/span><\/span><\/span><\/span><\/span>, is<br \/><img class=\"alignnone size-full wp-image-67160\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q2.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q2.1\" width=\"283\" height=\"85\" \/><\/p>\n<p><br \/>Solution:<br \/>Radius of a cone = 2r<br \/><img class=\"alignnone size-full wp-image-67161\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q2.2.png\" sizes=\"(max-width: 333px) 100vw, 333px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q2.2.png 333w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q2.2-300x134.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q2.2\" width=\"333\" height=\"149\" \/><\/p>\n<p>Question 3.<br \/>The total surface area of a cone of radius\u00a0<span id=\"MathJax-Element-2-Frame\" class=\"MathJax\" tabindex=\"0\"><span id=\"MathJax-Span-6\" class=\"math\"><span id=\"MathJax-Span-7\" class=\"mrow\"><span id=\"MathJax-Span-8\" class=\"mfrac\"><span id=\"MathJax-Span-9\" class=\"mi\">r<\/span><span id=\"MathJax-Span-10\" class=\"mn\">2<\/span><\/span><\/span><\/span><\/span>\u00a0and length 2l, is<br \/><img class=\"alignnone size-full wp-image-67162\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.1.png\" sizes=\"(max-width: 345px) 100vw, 345px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.1.png 345w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.1-300x231.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q3.1\" width=\"345\" height=\"266\" \/><br \/>Solution:<br \/><img class=\"alignnone size-full wp-image-67163\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.2.png\" sizes=\"(max-width: 356px) 100vw, 356px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.2.png 356w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q3.2-300x228.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q3.2\" width=\"356\" height=\"271\" \/><\/p>\n<p>Question 4.<br \/>A solid cylinder is melted and cast into a cone of same radius. The heights of the cone and cylinder are in the ratio<br \/>(a) 9 : 1<br \/>(b) 1 : 9<br \/>(c) 3 : 1<br \/>(d) 1 : 3<br \/>Solution:<br \/>Let r be the radius and h be the height of cylinder, then volume = \u03c0r<sup>2<\/sup>h<br \/>Now volume of cone = \u03c0r<sup>2<\/sup>h<br \/>r is the radius<br \/><img class=\"alignnone size-full wp-image-67164\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q4.1.png\" sizes=\"(max-width: 355px) 100vw, 355px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q4.1.png 355w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q4.1-300x124.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q4.1\" width=\"355\" height=\"147\" \/><\/p>\n<div class=\"code-block code-block-3\">\n<div id=\"div-gpt-ad-1699161877916-0\" data-google-query-id=\"CLjqtYyn1IIDFWdbnQkd3a8KUQ\">\n<div id=\"google_ads_iframe_\/22987339172\/insta_BANNER_300x250_051123_2_0__container__\">\u00a0<\/div>\n<\/div>\n<\/div>\n<p>Question 5.<br \/>If the radius of the base of a right circular cone is 3r and its height is equal to the radius of the base, then its volume is<br \/><img class=\"alignnone size-full wp-image-67165\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q5.1.png\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q5.1\" width=\"261\" height=\"86\" \/><br \/>Solution:<br \/>Radius of the base of a cone (R) = 3r<br \/>and height (H) = 3r<br \/><img class=\"alignnone size-full wp-image-67166\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q5.2.png\" sizes=\"(max-width: 352px) 100vw, 352px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q5.2.png 352w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q5.2-300x95.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q5.2\" width=\"352\" height=\"112\" \/><\/p>\n<p>Question 6.<br \/>If the volumes of two cones are in the ratio 1 : 4 and their diameters are in the ratio 4 : 5, then the ratio of their heights, is<br \/>(a) 1 : 5<br \/>(b) 5 : 4<br \/>(c) 5 : 16<br \/>(d) 25 : 64<br \/>Solution:<br \/>Ratio in the volumes of two cones =1:4<br \/>and ratio in their diameter = 4:5<br \/>Let h<sub>1<\/sub>, h<sub>2<\/sub>\u00a0be their heights<br \/><img class=\"alignnone size-full wp-image-67167\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.1.png\" sizes=\"(max-width: 314px) 100vw, 314px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.1.png 314w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.1-300x268.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q6.1\" width=\"314\" height=\"281\" \/><br \/><img class=\"alignnone size-full wp-image-67168\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.2.png\" sizes=\"(max-width: 378px) 100vw, 378px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.2.png 378w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q6.2-258x300.png 258w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q6.2\" width=\"378\" height=\"439\" \/><\/p>\n<div class=\"code-block code-block-4\">\n<div id=\"div-gpt-ad-1699162041532-0\">\u00a0<\/div>\n<\/div>\n<p>Question 7.<br \/>The curved surface area of one cone is twice that of the other while the slant height of the latter is twice that of the former. The ratio of their radii is<br \/>(a) 2 : 1<br \/>(b) 4 : 1<br \/>(c) 8 : 1<br \/>(d) 1 : 1<br \/>Solution:<br \/>Let r be the radius and l be the slant height<br \/>\u2234 Curved surface area of first cone = \u03c0r<sub>1<\/sub>l<sub>1<\/sub><br \/>and let curved surface area of second cone = \u03c0r<sub>2<\/sub>l<sub>2<\/sub><br \/><img class=\"alignnone size-full wp-image-67169\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q7.1.png\" sizes=\"(max-width: 351px) 100vw, 351px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q7.1.png 351w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q7.1-281x300.png 281w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q7.1\" width=\"351\" height=\"375\" \/><\/p>\n<p>Question 8.<br \/>If the height and radius of a cone of volume V are doubled, then the volume of the cone, is<br \/>(a) 3V<br \/>(b) 4V<br \/>(c) 6V<br \/>(d) 8V<br \/>Solution:<br \/>Let r and h be the radius and height of a cone, then<br \/><img class=\"alignnone size-full wp-image-67170\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q8.1.png\" sizes=\"(max-width: 344px) 100vw, 344px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q8.1.png 344w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q8.1-300x280.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q8.1\" width=\"344\" height=\"321\" \/><\/p>\n<div class=\"code-block code-block-5\">\n<div id=\"div-gpt-ad-1699162127327-0\">\u00a0<\/div>\n<\/div>\n<p>Question 9.<br \/>The ratio of the volume of a right circular cylinder and a right circular cone of the same base and height, is<br \/>(a) 1 : 3<br \/>(b) 3 : 1<br \/>(c) 4 : 3<br \/>(d) 3 : 4<br \/>Solution:<br \/>Let r be the radius and h be the height of a right circular cylinder and a right circular cone, and V<sub>1<\/sub>\u00a0and V<sub>2<\/sub>\u00a0are their volumes, the V<sub>1<\/sub>\u00a0=\u00a0 \u03c0r<sup>2<\/sup>h and<br \/><img class=\"alignnone size-full wp-image-67171\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q9.1.png\" sizes=\"(max-width: 352px) 100vw, 352px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q9.1.png 352w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q9.1-300x200.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q9.1\" width=\"352\" height=\"235\" \/><\/p>\n<p>Question 10.<br \/>A right cylinder and a right circular cone have the same radius and same volumes. The ratio of the height of the cylinder to that of the cone is<br \/>(a) 3 : 5<br \/>(b) 2 : 5<br \/>(c) 3 : 1<br \/>(d) 1 : 3<br \/>Solution:<br \/>Let r be the radius of cylinder and cone and volumes are equal<br \/>and h<sub>1<\/sub>, and h<sub>2<\/sub>\u00a0be their have h<sub>2<\/sub>\u00a0is respectively<br \/><img class=\"alignnone size-full wp-image-67173\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q10.1.png\" sizes=\"(max-width: 359px) 100vw, 359px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q10.1.png 359w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q10.1-300x242.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q10.1\" width=\"359\" height=\"290\" \/><\/p>\n<p>Question 11.<br \/>The diameters of two cones are equal. If their slant heights are in the ratio 5 : 4, the ratio of their curved surface areas, is<br \/>(a) 4 : 5<br \/>(b) 25 : 16<br \/>(c) 16 : 25<br \/>(d) 5 : 4<br \/>Solution:<br \/>\u2235 Diameters of two cones are equal<br \/>\u2234 Their radii are also be equal<br \/>Let r be their radius of each cone,<br \/>and ratio in their slant heights = 5:4<br \/>Let slant height of first cone (h<sub>1<\/sub>) = 5x<br \/>Then height of second cone (h<sub>2<\/sub>) = 4x<br \/><img class=\"alignnone size-full wp-image-67174\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q11.1.png\" sizes=\"(max-width: 346px) 100vw, 346px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q11.1.png 346w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q11.1-300x130.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q11.1\" width=\"346\" height=\"150\" \/><\/p>\n<p>Question 12.<br \/>If the heights of two cones are in the ratio of 1 : 4 and the radii of their bases are in the ratio 4 : 1, then the ratio of their volumes is<br \/>(a) 1 : 2<br \/>(b) 2 : 3<br \/>(c) 3 : 4<br \/>(d) 4 : 1<br \/>Solution:<br \/>Ratio in the heights of two cones =1 : 4<br \/>and ratio in their radii of their bases = 4 : 1<br \/>Let height of the first cone = x<br \/>and height of the second cone = 4x<br \/>Radius of the first cone = 4y<br \/>and radius of the second cone = y<br \/><img class=\"alignnone size-full wp-image-67175\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.1.png\" sizes=\"(max-width: 296px) 100vw, 296px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.1.png 296w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.1-216x300.png 216w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q12.1\" width=\"296\" height=\"411\" \/><\/p>\n<p><img class=\"alignnone size-full wp-image-67176\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.2.png\" sizes=\"(max-width: 357px) 100vw, 357px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.2.png 357w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q12.2-300x122.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q12.2\" width=\"357\" height=\"145\" \/><\/p>\n<p>Question 13.<br \/>The slant height of a cone is increased by 10%. If the radius remains the same, the curved surface area is increased by<br \/>(a) 10%<br \/>(b) 12.1%<br \/>(c) 20%<br \/>(d) 21%<br \/>Solution:<br \/>Let r be radius and l be the slant height of a cone, then curved surface area = \u03c0rl<br \/>If slant height is increased by 10%, then<br \/><img class=\"alignnone size-full wp-image-67177\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q13.1.png\" sizes=\"(max-width: 346px) 100vw, 346px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q13.1.png 346w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q13.1-296x300.png 296w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q13.1-100x100.png 100w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q13.1\" width=\"346\" height=\"351\" \/><\/p>\n<p>Question 14.<br \/>The height of a solid cone is 12 cm and the area of the circular base is 6471 cm<sup>2<\/sup>. A plane parallel to the base of the cone cuts through the cone 9 cm above the vertex of the cone, the area of the base of the new cone so formed is<br \/>(a) 9\u03c0 cm<sup>2<\/sup><br \/>(b) 16\u03c0 cm<sup>2<\/sup><br \/>(c) 25\u03c0 cm<sup>2<\/sup><br \/>(d) 36\u03c0 cm<sup>2<\/sup><br \/>Solution:<br \/>Height of a solid cone (h) = 12 cm<br \/>Area of circular base = 64\u03c0 cm<sup>2<\/sup><br \/><img class=\"alignnone size-full wp-image-67178\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.1.png\" sizes=\"(max-width: 297px) 100vw, 297px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.1.png 297w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.1-247x300.png 247w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q14.1\" width=\"297\" height=\"361\" \/><br \/><img class=\"alignnone size-full wp-image-67179\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.2.png\" sizes=\"(max-width: 370px) 100vw, 370px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.2.png 370w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q14.2-300x254.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q14.2\" width=\"370\" height=\"313\" \/><\/p>\n<p>Question 15.<br \/>If the base radius and the height of a right circular cone are increased by 20%, then the percentage increase in volume is approximately<br \/>(a) 60<br \/>(b) 68<br \/>(c) 73<br \/>(d) 78<br \/>Solution:<br \/>In first case,<br \/>Let r be radius and h be height, in volume<br \/><img class=\"alignnone size-full wp-image-67180\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.1.png\" sizes=\"(max-width: 339px) 100vw, 339px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.1.png 339w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.1-270x300.png 270w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q15.1\" width=\"339\" height=\"376\" \/><br \/><img class=\"alignnone size-full wp-image-67181\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.2.png\" sizes=\"(max-width: 363px) 100vw, 363px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.2.png 363w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q15.2-300x215.png 300w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q15.2\" width=\"363\" height=\"260\" \/><\/p>\n<p>Question 16.<br \/>If h, S and V denote respectively the height, curved surface area and volume of a right circular cone, then 3\u03c0Vh<sup>3<\/sup>\u00a0\u2013 S2h<sup>2<\/sup>\u00a0+ 9V<sup>2<\/sup>\u00a0is equal to<br \/>(a) 8<br \/>(b) 0<br \/>(c) 4\u03c0<br \/>(d) 32\u03c0<sup>2<\/sup><br \/>Solution:<br \/>h = height, S = curved surface area<br \/>V = volume of a cone<br \/>Let r be the radius of the cone, then<br \/><img class=\"alignnone size-full wp-image-67182\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q16.1.png\" sizes=\"(max-width: 355px) 100vw, 355px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q16.1.png 355w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q16.1-300x297.png 300w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q16.1-150x150.png 150w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q16.1-100x100.png 100w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q16.1\" width=\"355\" height=\"352\" \/><\/p>\n<p>Question 17.<br \/>If a cone is cut into two parts by a horizontal plane passing through the mid\u00acpoint of its axis, the ratio of the volumes of upper and lower part is<br \/>(a) 1 : 2<br \/>(b) 2 : 1<br \/>(c) 1 : 7<br \/>(d) 1 : 8<br \/>Solution:<br \/>\u2234 \u2206PDC ~ \u2206PBA (AA axiom)<br \/>and O\u2019 is mid point of PO<br \/><img class=\"alignnone size-full wp-image-67183\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.1.png\" sizes=\"(max-width: 338px) 100vw, 338px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.1.png 338w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.1-226x300.png 226w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q17.1\" width=\"338\" height=\"448\" \/><br \/><img class=\"alignnone size-full wp-image-67184\" src=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.2.png\" sizes=\"(max-width: 363px) 100vw, 363px\" srcset=\"https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.2.png 363w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.2-300x298.png 300w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.2-150x150.png 150w, https:\/\/www.learninsta.com\/wp-content\/uploads\/2020\/11\/RD-Sharma-Class-9-Solutions-Chapter-20-Surface-Areas-and-Volume-of-A-Right-Circular-Cone-MCQS-Q17.2-100x100.png 100w\" alt=\"RD Sharma Class 9 Solutions Chapter 20 Surface Areas and Volume of A Right Circular Cone MCQS Q17.2\" width=\"363\" height=\"361\" \/><\/p>\n<p>We have included all the information regarding <a href=\"https:\/\/cbse.nic.in\/\" target=\"_blank\" rel=\"noopener\">CBSE<\/a> <strong>RD Sharma Class 9 Solutions Chapter 20 MCQs<\/strong><span data-sheets-value=\"{&quot;1&quot;:2,&quot;2&quot;:&quot;RD Sharma Class 9 Solutions Chapter 20 Exercise 20.1&quot;}\" data-sheets-userformat=\"{&quot;2&quot;:4540,&quot;5&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;6&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;7&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;8&quot;:{&quot;1&quot;:[{&quot;1&quot;:2,&quot;2&quot;:0,&quot;5&quot;:[null,2,0]},{&quot;1&quot;:0,&quot;2&quot;:0,&quot;3&quot;:3},{&quot;1&quot;:1,&quot;2&quot;:0,&quot;4&quot;:1}]},&quot;10&quot;:2,&quot;11&quot;:0,&quot;15&quot;:&quot;Arial&quot;}\">. If you have any queries feel free to ask in the comment section.\u00a0<\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"faq-rd-sharma-class-9-solutions-chapter-20-mcqs\"><\/span>FAQ: <strong>RD Sharma Class 9 Solutions Chapter 20 MCQs<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n<div id=\"rank-math-faq\" class=\"rank-math-block\">\n<div class=\"rank-math-list \">\n<div id=\"faq-question-1630932996497\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"can-i-download-rd-sharma-class-9-solutions-chapter-20-mcqs-pdf-free\"><\/span>Can I download RD Sharma Class 9 Solutions Chapter 20 MCQs PDF free?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>Yes, you can download RD Sharma Class 9 Solutions Chapter 20 MCQs PDF free.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630933023556\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"what-are-the-benefits-of-studying-rd-sharma-class-9-solutions-chapter-20-mcqs\"><\/span>What are the benefits of studying RD Sharma Class 9 Solutions Chapter 20 MCQs?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>By practicing these RD Sharma Class 9 Solutions Chapter 20 MCQs, students can earn higher academic grades. Our experts solve these solutions with utmost accuracy to help students in their studies.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"faq-question-1630933026956\" class=\"rank-math-list-item\">\n<h3 class=\"rank-math-question \"><span class=\"ez-toc-section\" id=\"is-rd-sharma-enough-for-class-12-maths\"><\/span>Is RD Sharma enough for Class 12 Maths?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<div class=\"rank-math-answer \">\n\n<p>RD Sharma is a good book that gives you thousands of questions to practice.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>RD Sharma Class 9 Solutions Chapter 20 MCQs:\u00a0You can easily download the RD Sharma Class 9 Chapter 20 MCQs solutions. These solutions are created by our experts and you can easily download them in PDF format. The RD Sharma solutions will benefit you in scoring good marks in Class 9 Maths exams. You can easily &#8230; <a title=\"RD Sharma Class 9 Solutions Chapter 20 MCQs (Updated for 2024)\" class=\"read-more\" href=\"https:\/\/www.kopykitab.com\/blog\/rd-sharma-class-9-solutions-chapter-20-mcqs\/\" aria-label=\"More on RD Sharma Class 9 Solutions Chapter 20 MCQs (Updated for 2024)\">Read more<\/a><\/p>\n","protected":false},"author":244,"featured_media":125622,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"fifu_image_url":"","fifu_image_alt":""},"categories":[73719],"tags":[76791,4388],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/124870"}],"collection":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/users\/244"}],"replies":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/comments?post=124870"}],"version-history":[{"count":4,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/124870\/revisions"}],"predecessor-version":[{"id":510033,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/posts\/124870\/revisions\/510033"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media\/125622"}],"wp:attachment":[{"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/media?parent=124870"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/categories?post=124870"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.kopykitab.com\/blog\/wp-json\/wp\/v2\/tags?post=124870"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}