RS Aggarwal Class 8 Maths Chapter 18 Ex 18.1 Solutions: In this exercise, the students will study the basic application of formulas based on squares, rectangles, triangles, parallelograms, and rhombuses. The solutions are designed by our Mathematics expert faculty team keeping in mind the latest CBSE syllabus to assist the students to score good marks in their exams. The students can easily download & the solutions PDF which makes them prepare for their exams in a better way.
The students can refer to RS Aggarwal Class 8 Maths Chapter 18 Ex 18.1 Solutions & can download the PDF from the link provided below for better learning of the concepts. They are suggested to practice the exercise solutions regularly which also builds up their confidence level. They can download these solutions PDFs free of cost & get the details of all concepts covered in this exercise. The solutions give the students a detailed & in-depth understanding of all the questions & concepts of this chapter.
Access RS Aggarwal Class 8 Maths Chapter 18 Solutions PDF
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RS Aggarwal Class 8 Maths Chapter 18 Ex 18.1 Solutions
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It is a quadrilateral in which the pairs of opposite sides are parallel. The lengths of the opposite sides are also equal. In a parallelogram ABCD, AB is parallel to CD & AD is parallel to BC. Also, AB = CD and AD = BC.
The angles are not right angles in a parallelogram. The sum of the angles is 360° & the opposite angles are equal. To find the area of a parallelogram, the students need to multiply its base by its height. Hence, the formula is Area of Parallelogram = b × h
It is a quadrilateral in which the pairs of opposite sides are parallel. All sides are equal in length. The angles in a rhombus are congruent to each other. All diagonals are perpendicular bisectors of the other. They cut each other in half & intersect each other at right angles. The area can be calculated as:
If the height & base are given, the Area of Rhombus = b × h
When the length of the diagonals is given, the Area of Rhombus = (d1 x d2)/2
where d1 is the diagonal & d2 is the length of the other diagonal.
The formula to find the perimeter is P = 4s where s is the length of the side.
If measure the pair of sides we find that the parallel sides are equal in length too. A rectangle can be considered to be a parallelogram with equal angles as the angles in a rectangle are equal.
In a square, all sides share an equal length. The diagonals in a square show the given below properties:
They bisect one another
The diagonals are of equal length
Each diagonal is perpendicular to one other
It is a 3-sided polygon.
Area of triangle = ½ × Base × Height
A = ½ bh
RS Aggarwal Class 8 Math Exercise 18A PDF is designed to give students an in-depth understanding of the concepts of the chapter and the different types of questions asked in the examination. Practicing questions from RS Aggarwal Class 8 exercise 18 will make the students familiar with what types of questions are commonly asked in the examinations. For a precise and logical explanation of these questions download the RS Aggarwal Solutions Class 8 Math ex 18A PDF.
It is critical to put consistent efforts into practicing word problems and understanding the figures to answer the questions from this chapter. Benefits of RS Aggarwal Solutions Class 8 ex 18 a are given below:
The solutions are prepared by our subject experts at Vedantu with years of experience in teaching.
The answers are written simply and logically to improve concept-based understanding.
The solutions are prepared as per the CBSE guidelines to help students score well in their exams.
Practicing solutions from the RS Aggarwal Math Class 8 ex 18A will allow students to format their answers in the exams better.
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