JNTU Question Papers
Chemical And Bio Thermodynamics 1st Sem November 2008
1. Explain the formulation of the first law of Thermodynamics and illustrate any two
2. Write short notes: [4×4=16]
(a) Explain the Carnot refrigeration cycle.
(b) Write about the air refrigeration cycle.
(c) Compare the refrigeration cycles.
(d) Write about the choice of refrigerant.
3. (a) Explain clausius-Clayperyon equation?
(b) Mercury has a density of 13.69_103kg/m3 in the liquid state and 14.193_103kg/m3
in the solid state, both measured at the melting point of 234.33 K at 1 bar.
If the heat of fusion of mercury is 9.7876 kJ/kg, what is the melting point of
mercury at 10 bar? [8+8]
4. Estimate ?1 and ?2 for an equimolar mixture of methyl ethyl ketone (1)/toluene(2)
at 500 C and 25 kPa. Set all kij = 0. The required data are as follows. 
ij Tcij Pcij(bar) Vcij(cm3/mol) Zcij ?ij
11 53505 41.5 267 0.249 0.323
22 591.8 41.1 316 0.264 0.262
12 563.0 41.3 291 0.256 0.293
5. Discuss the correlation between Raoult’s law and bubble point. 
6. The water-gas-shift reaction;
CO(g) + H2O(g) ? ? ? ? ? ?CO2(g) + H2(g)
Is carrier out under the different sets of conditions described below? Calculate the
fraction of steam reacted in each case. Assume the mixture behave as an ideal gas.
(a) The reactants consist of 1 mol of H2O vapour and 1 mol of CO. The temper-
ature is 1100K and the pressure is 1 bar.
(b) Same as (a) except that the pressure is 10bar.
(c) Same as (a) accept that 2 Mol of N2 is included in the reactants.
(d) The reactants are 2 mol of H2O and 1 mol of CO. other conditions are the
same as in
(e) The reactants are 1 mol of H2O and 2 mol of CO. other conditions are the same as in
(f) The initial mixture consists of 1mol of H2O, 1 mol of CO, and 1 Mol of CO2
other conditions are the same as in (a).
(g) Same as (a) except that the temperature is 1650K. [3+3+2+2+2+2+2]
7. (a) Explain the Gaden classification from stoichiometric point of view the product
formation in fermentation processes.
(b) The following stoichiometric equation describes penicillin systhesis
1.5Glucose+H2SO4+2NH3 + phenyl acetate! Pencillium G + CO2+8H2O the theoretical yield of pencillium is 1.2g/(gram of glucose). Find out the molecular weight of pencillium G. [8+8]
8. Discuss the average yield coefficient for activated sludge.