# CUSAT Previous Question Papers BE CE 4th Semester

# Surveying-II April 2011

I. (a) Explain briefly the elements of a simple curve.

(b) Two tangents intersect at the chainage of 1190m, the deflection angle being 36°. Calculate all the data necessary for setting out a curve with a radius of300m by deflection angle method. The peg interval is 30m.

**OR**

II. (a) What is a transition curve? What are its advantages?

(b) The following data refers to a right-hand compound curve:

Total deflection angle = 80°

Radius of the first arc = 200m

Radius of the second arc = 250m

Chainage of the point of intersection = 1504.80m Deflection angle of the first arc = 50°

Determine the chainages of the point of curvature, the point of compound curve and the point of tangency.

III. (a) What is the principle of triangulation? Which are the factors to be considered in the selection of triangulation stations?

(b) There are two stations A and B at elevations of 200m and 1000m respectively. The distance between A & B is 100 km. If the elevation of a peak P at a distance of 40km from A is 300m. Show that the stations A and B are intervisible.

**OR**

IV. (a) What is a satellite station? How would you reduce the horizontal angles?

(b) A line was measured with a steel tape which was exactly 30m at 20°C at a pull of 100N. The measured length was 1500m. If the temperature during measurement was 28°C and the pull applied was 150N, determine the correct length of the line. Cross-sectional area of the tape = 2.5mm^{2} Coefficient of expansion = 3.5 x 10′^{6} per °C Modulus of elasticity = 2.1 x 10^{5}N/mm^{2}

V. (a) Which are the different laws of weights? Explain.

(b) Find the most probable value of the angles A,B and C of a triangle ABC from the (10) following observations:

^ = 65° 15’30’, weight 3 B = 51° 11′ 25″, weight 2 C = 63° 32′ 34″, weight 4

**OR**

VI. (a) What do you mean by the theory of least squares?

(b) Find the most probable values of the following angles closing the horizon at a station. (12)

P = 45° 23’37”, weight = 1 0 = 75° 37′ 15″, weight =2 R = 125° 21’21”, weight = 3 5 = 113° 37’59” weight = 3

VII. (a) Explain any one method of co-ordinate system for specifying the position of a celestial body.

(b) Determine the hour angle and declination of a star from the following data:

Altitude of the star =21° 30′

Azimuth of the star = 140° E

Latitude of the observer = 48° N OR

VIII. (a) Find the G.M.T. corresponding to the following L.M.T.

(i) 9^{h} 40^{m} 12^{s} A.M. at a place in longitude 42°36^{,}J’F

(ii) 4^{h} 32^{m} 10^{s} A.M. at a place in longitude 56°32′ E

(b) Explain the following terms:

(i) Equation of time

(ii) Sideral time

(ii) Sun dial

(iv) Standard time

IX. (a) Explain in brief the different methods of sounding.

(b) A, B and C are three triangulation stations on a coast line and P is a sounding point. in sea. Distance AB=1250m, BC=1310m,angle ABC —122°30′, angle

APB — 45°24′ and angle BPC = 48^{0}36^{,}. A and C are respectively west and east of BP where as P is south of B. Calculate the distances AP, BP and CP.

**OR**

X. (a) Write the comparison between Air photograph and Map. (b) A straight length of a highway AB appears to be 12.5cm on a vertical air photograph of 15cm focal length. The corresponding distance of the highway on a 1:50,000 topographical map is 6.25cm. Assuming the average elevation of the terrain as 1250m above M.S.L, calculate the flying height of the Camera above Mean Sea Level.